topic Re: Conditional output in Ansible in Code Exchange

Conditional output in Ansible

Netmart — Tue, 07 Nov 2023 07:29:15 GMT

Hello,

I wanted to print only one message when show run | eigrp output does contain "eigrp".

However, print result is skipped.

Please advise.

Thanks

Like:

---

- name: EIGRP Config Check

hosts: iosxe

vars_files:

- /home/cisco/Ansible/vault_password.yml

vars:

ansible_become_pass: "{{ vault_sudo_password }}"

ansible_python_interpreter: /usr/bin/python3

tasks:

- name: show run | sec eigrp

ios_command:

commands:

- show run | sec eigrp

become: true

- name: print result

debug:

var: output

msg: " EIGRP configured "

when: '"router eigrp" in output.stdout'

Re: Conditional output in Ansible

bigevilbeard — Tue, 07 Nov 2023 10:35:12 GMT

@Netmart i see you are using the when clause to check if the output of the show run | sec eigrp command contains the string "router eigrp". However, the output of this command will also contain other lines of configuration related to EIGRP, such as the network statements and the redistribute statements. As a result, the when clause will always evaluate to true, and the print result task will always be executed.

Hope this helps.

Re: Conditional output in Ansible

Netmart — Tue, 07 Nov 2023 16:30:56 GMT

Thank you.

Let me try to rephrase my question.

The goal is to implement an "if condition" by search for a string in a block of text

If the output of "show run | sec eigrp" does contain the string "eigrp", only print the message: "EIGRP config exists". Otherwise print the message "EIGRP does NOT exist".

Is this possible?

Or is way to utilize the Python find method like:

The find() method returns -1 if the value is not found.

Please advise.

Re: Conditional output in Ansible

Torbjørn — Tue, 07 Nov 2023 16:48:24 GMT

This condition should work for your purposes:

when: output.stdout is search("router eigrp")

Re: Conditional output in Ansible

bigevilbeard — Tue, 07 Nov 2023 17:47:30 GMT

You could implement an "if condition" to search for a string in a block of text using Ansible. Like you can use the find() filter to search for the string in the output.stdout variable. The find() filter returns the index of the first occurrence of the string, or -1 if the string is not found

Hope this helps.

Re: Conditional output in Ansible

Netmart — Mon, 13 Nov 2023 04:48:12 GMT

Thank you Torbjorn.

This seems to work.

Is it possible to expand this condition, by printing a message if EIGRP config is not found.

Like:

- name: print result

debug:

#var: output

msg: " EIGRP configured "

when: output.stdout is search("router eigrp")

- name: print result

debug:

#var: output

msg: " EIGRP NOT configured "

when: if output.stdout is search(=!\"router eigrp\")

Re: Conditional output in Ansible

Torbjørn — Mon, 13 Nov 2023 06:29:58 GMT

No problem! Yes, that can be done. You can use a second task with the following when statement/condition:

when: output.stdout is not search("router eigrp")