topic Re: Getting everything in a list object without creating a filter in Tools

Getting everything in a list object without creating a filter

MahdiR — Thu, 11 Mar 2021 08:31:07 GMT

Is there a way to get everything that a list contains without having to provide the keys for all elements in the list and getting them individually?

I.e. "ydk.models.ietf.ietf_diffserv_policy" contains a class "Policies" which again contains a list "PolicyEntry". Can I get all data from this list all at once? or do I have to get them one by one by creating a filter and providing their corresponding key "policy_name"?

Re: Getting everything in a list object without creating a filter

yangorelik — Fri, 12 Mar 2021 19:11:40 GMT

Yes, you can get the entire content of the list in YDK-0.8.5. The examples for such CRUD Service operations are present in the online documentation. In short, you need instantiate one list element without configuring any key and set a read filter operation on it. Here is a peace from the documented example, where we try to get route table from deeply rooted YANG model Cisco_IOS_XR_ip_rib_ipv4_oper.yang:

# Create the list member instance Route()
route = Cisco_IOS_XR_ip_rib_ipv4_oper.Rib.Vrfs.Vrf.Afs.Af.Safs.Saf.IpRibRouteTableNames.IpRibRouteTableName.Routes.Route()

# Set the yfilter attribute for the route instance
route.yfilter = YFilter.read

# Append the list element instance to its respective parent
# (all the parent classes up to the top level container must be instantiated!!)
table_name = Cisco_IOS_XR_ip_rib_ipv4_oper.Rib.Vrfs.Vrf.Afs.Af.Safs.Saf.IpRibRouteTableNames.IpRibRouteTableName()
table_name.route_table_name = 'default'
table_name.routes.route.append(route)

# Read the list
route_table = crud.read(provider, table_names)

Re: Getting everything in a list object without creating a filter

MahdiR — Mon, 15 Mar 2021 09:14:29 GMT

Thank you Yan!

Your help as always is appreciated.