How to setup Python loop to create 3000 ACI BDs

[chungewa]

HI, Experts

from the following 2 python line script，it can create ONE BD into the tenant,

BUT what i need is creating 3000 BDs,

So how can i setup a Python loop to dynamically replace the following colorful text

Thanks a lot!

/Ja

==========================

    fvBD8 = cobra.model.fv.BD(fvTenant, ownerKey=u'', name=u'BD8', descr=u'', unkMacUcastAct=u'proxy', arpFlood=u'no', mac=u'00:22:BD:F8:19:FF', unicastRoute=u'yes', ownerTag=u'', unkMcastAct=u'flood')

    fvRsABDPolMonPol8 = cobra.model.fv.RsABDPolMonPol(fvBD8, tnMonEPGPolName=u'default')

=========================

[tigephillips · Accepted solution]

for num in range (1,3001):

  my_string =  "fvBD{0} = cobra.model.fv.BD(fvTenant, ownerKey=u'', name=u'BD{0}', descr=u'', unkMacUcastAct=u'proxy', arpFlood=u'no', mac=u'00:22:BD:F8:19:FF', unicastRoute=u'yes', ownerTag=u'', unkMcastAct=u'flood') fvRsABDPolMonPol{0} = cobra.model.fv.RsABDPolMonPol(fvBD{0}, tnMonEPGPolName=u'default')".format (num)

  print my_string

This will change each of the {0} in the string into whatever is in "num".   The other key to the code is the .format (num)   on the end of the string.  I'm printing it out, but you probably will want to do something with it instead.  You will get numbers from 1 - 3000 (range gives you one less than what you specify).

[chungewa]

thanks tiphilli！！！