11-02-2012 07:20 AM - edited 03-13-2019 08:02 PM
Anyone know what the max number of callers that can be on one line?
Solved! Go to Solution.
11-02-2012 07:43 AM
Hi Pete,
Don't forget that these numbers will also need to be
balanced with your PSTN access (PRI's etc.)
Cisco Conference Bridge Software
Software conference devices support G.711 codecs by default.
The maximum number of audio streams for this type equals 128. With 128 streams, a software conference media resource can handle 128 users in a single conference, or the software conference media resource can handle up to 42 conferencing resources with three users per conference.
The default number of Maximum MeetMe Participants (per Conference) is set at 4.
To increase the Maximum number of MeetMe participants (we have ours at 16);
Go to:
Service Parameters Configuration >Clusterwide Parameters (Service)>Maximum MeetMe Conference
With the Software Conference Bridge;
128 Streams
128 with 48 Users in each = 3
128 with 24 Users in each = 6
128 with 16 Users in each = 8
128 with 8 Users in each = 16
128 with 4 Users in each = 32
Cheers!
Rob
"And if I should fall behind
Wait for me" - Springsteen
11-02-2012 07:43 AM
Hi Pete,
Don't forget that these numbers will also need to be
balanced with your PSTN access (PRI's etc.)
Cisco Conference Bridge Software
Software conference devices support G.711 codecs by default.
The maximum number of audio streams for this type equals 128. With 128 streams, a software conference media resource can handle 128 users in a single conference, or the software conference media resource can handle up to 42 conferencing resources with three users per conference.
The default number of Maximum MeetMe Participants (per Conference) is set at 4.
To increase the Maximum number of MeetMe participants (we have ours at 16);
Go to:
Service Parameters Configuration >Clusterwide Parameters (Service)>Maximum MeetMe Conference
With the Software Conference Bridge;
128 Streams
128 with 48 Users in each = 3
128 with 24 Users in each = 6
128 with 16 Users in each = 8
128 with 8 Users in each = 16
128 with 4 Users in each = 32
Cheers!
Rob
"And if I should fall behind
Wait for me" - Springsteen
11-02-2012 09:35 AM
Thanks, Rob
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