cancel
Showing results for
Did you mean:
cancel
731
Views
0
4
Replies

## EIGRP Variance & Traffic distribution count   Enthusiast

Hello All,

Have a question on the EIGRP traffic distribution count. Is there a possibility to perform the traffic distribution in 5:2 ?  Below is the calculation to perform a 5:1 ratio distribution  (Diagram is attached for the setup).

Note : Using only delay to perform the composite metric calculation

Path via R2 from R1 to reach Loopback on R4

Metric = 256*[sum of delay/10]

=256*[10+10+500]

=256*520

=133120

Path via R3 from R1 to reach Loopback on R4

=256*2510=642560

So. Path via R2 would be successor & path via R3

As Feasible successor.

Variance = FD of FS/FD of Successor

So, 642560/133120 = 4.82

Variance = 5 (whole number)

Lowest metric (FD of the successor)* 5 = 256 * [delay/10]

So, looking at my metric figures

133120 x 5 = 256 * [delay/10]

665600/256 = delay/10

26000 = delay

Now, to determine the local interface delay (LD), we need to subtract the relative distance delay in order to get the LD.

R3 - R4 has a cumulative delay of 5100.

So, 26000 - 5100 = 20900

Now, by setting the delay value of 2090 on the R1 interface connecting to R3, i would achieve 5:1. What can be done to get 5:2 ?

Thanks

Vivek

1 Accepted Solution

Accepted Solutions    Hall of Fame Master

Hello Vivek,

133120 x 5 = 256 * [delay/10]

you would use the following:

133120 x 5/2 = 256 * [delay/10]

you get total delay = 13000

you subtract the known delay components and you get

dx = 13000 - 5100 = 7900

so by setting interface delay to 790 tens of microseconds you should get a 5:2 ratio in the metric values on the two paths

Let's verify:

790+10+500 = 1300

on the other path you have

10+10+500  = 520

1300 /520 = 2,5 = 5/2

Hope to help

Giuseppe

4 Replies 4   Beginner

Interesting,I am also looking for this solution..

-bava    Hall of Fame Master

Hello Vivek,

133120 x 5 = 256 * [delay/10]

you would use the following:

133120 x 5/2 = 256 * [delay/10]

you get total delay = 13000

you subtract the known delay components and you get

dx = 13000 - 5100 = 7900

so by setting interface delay to 790 tens of microseconds you should get a 5:2 ratio in the metric values on the two paths

Let's verify:

790+10+500 = 1300

on the other path you have

10+10+500  = 520

1300 /520 = 2,5 = 5/2

Hope to help

Giuseppe   Enthusiast

Hi Giuseppe

This was very helpful. I have been struggling on the math for quite a long time on this. I will test this in my lab tonight & update the post.

Again, a great help !!

Regards

Vivek   Beginner

Execellent Giuseppe...!! Thanks for the post Vivek Getting Started

Find answers to your questions by entering keywords or phrases in the Search bar above. New here? Use these resources to familiarize yourself with the community: 