09-20-2019 10:28 AM
I have trying to make this exercice about Summarization,
After my calculations I tought the correct answer maybe B, D and E, the simulator says the correct is B and E, why they are the answer and not E and D for example?
Thanks!
Solved! Go to Solution.
09-20-2019 11:21 AM
Hi @RennyGalindez ,
After summarizing the networks, the result was:
192.168.176.0/21 = 192.168.1011 0|000.0
This indicates that the networks connected to R2 must be equal until the cut of the mask (/21)
Options A and C do not meet this condition, so they are not one of the networks connected to R2.
Option B meets the condition:
192.168.183.41 = 192.168.1011 0111.0010 1001
Option E meets the condition:
192.168.179.4 = 192.168.1011 0011.0000 0100
Option D meets the condition, but it is a broadcast address, so it will not be a viable destination ip (only unicast addresses are routed from one router to another):
192.168.183.255 = 192.168.1011 0111.1111 1111
Regards
09-20-2019 11:21 AM
Hi @RennyGalindez ,
After summarizing the networks, the result was:
192.168.176.0/21 = 192.168.1011 0|000.0
This indicates that the networks connected to R2 must be equal until the cut of the mask (/21)
Options A and C do not meet this condition, so they are not one of the networks connected to R2.
Option B meets the condition:
192.168.183.41 = 192.168.1011 0111.0010 1001
Option E meets the condition:
192.168.179.4 = 192.168.1011 0011.0000 0100
Option D meets the condition, but it is a broadcast address, so it will not be a viable destination ip (only unicast addresses are routed from one router to another):
192.168.183.255 = 192.168.1011 0111.1111 1111
Regards
09-20-2019 11:37 AM
Hi Luis,
> Option D meets the condition, but it is a broadcast address, so it will not be a viable destination ip (only unicast addresses are > routed from one router to another):
This subnet is not directly connected, therefore this would not prevent traffic to this destination from being forwarded from R1 to R2.
Regards,
09-20-2019 11:28 AM
You are correct. D is also correct. R1 would forward packets with destination address 192.168.183.255 to R2.
Regards,
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