09-18-2017 04:19 AM - edited 03-08-2019 12:04 PM
Hi community,
could someone explain me which is algorithm selection for multicast group when 2 RP are configured.
If i remember well (sorry I didn't find nothing on Internet), RP with highest IP address wins, right ?
For example:
ip access-list standard RP-TEST-01
permit 239.121.1.0 0.0.0.255
ip pim rp-address 1.1.1.1 RP-TEST-01 override
ip pim rp-address 2.2.2.2 RP-TEST-01 override
RP 2.2.2.2 wins, right ?
Another thing, what happen if defined groups for second RP are a subgroup of first RP.
Example:
ip access-list standard RP-TEST-01
permit 239.121.1.0 0.0.0.255
ip access-list standard RP-TEST-02
permit 239.121.1.0 0.0.0.127
ip pim rp-address 1.1.1.1 RP-TEST-01 override
ip pim rp-address 2.2.2.2 RP-TEST-02 override
Which is the RP for group "239.121.1.0" ?
Thank you for your help,
Marcello
09-19-2017 02:44 AM
Hi Marcello
Yes, You are right, the the highest ip address wins.For the next question, there is a longest match function.Therefore 2.2.2.2 is chosed for groups in the range 239.121.1.0 to 239.121.1.127
For groups in the range 239.121.1.128 to 239.121.1.255 1.1.1.1 is rp
/Mikael
09-19-2017 04:30 AM
10-02-2017 06:27 AM
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