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Hi,I am studying for CCNA and right now going through Subnetting section. Came across this question : What is the default subnet mask for ip address 192.168.10.7 / 10? If my requirement is to connect 1000 hosts then how many subnets, hosts per subnet...
For 150.250.150.250/23 my subnet mask is 255.255.254.0. Now i borrow 2 more network bits from host bits so new mask is 255.255.255.128. Right?Here increment bit give 128 as the decimal value.the network will be then :150.250.150.0 and 150.250.150.128...
Hi,How hav you arrived at change in first octet from 192 to 197?the calculation for 192.168.10.7/10 will be like :Ist Subnet : 192.0.0.0Range : 192.0.0.1 to 192.63.255.254Broadcast : 192.63.255.2552nd subnet : 192.64.0.0Range : 192.64.0.1 to 192.12...
Hello Narendrakumar B,That was indeed helpful.Do you know whether this technique works with cidr also?ex. 150.250.150.250/23 is the ip address.requirement is total 3 networks?ThanxMahima
hello Ganeshu are making me confused. A /10 cidr means i have 2 subnet bits which give 2^2 = 4 networks and remainings bits are the host bits (22) which definitely give more than 1000 hosts. According to Todd calculation, there will be four network, ...
Hello Ganesh,So here, 192.168.10.7 is class C address with class A subnet mask and this is possible because of supernetting.Is this what you mean to say?I got your last part that there will be four subnets with 64 block size starting from 0, 64, 128...
