03-14-2006 08:00 AM - edited 03-09-2019 02:15 PM
Hi,
I have a question about how the allocation of addresses is performed from a global pool defined on a Pix.
I have a NAT setup on my inside interface and a corresponding global statement. i want to NAT an inside subnet to the same size subnet.
My question is how are the addresses allocated from the global pool, are they 1-1 therfore .1 on the inside would always be .1 on the outside or are they first come first served ?
Any help would be appreciated.
Thanks
Stu
03-14-2006 09:46 AM
If you NAT/GLOBAL a /24 then the clients first came were first served ! The NAT is done dynamicly when clients connect to the internet.
sincerely
Patrick
03-14-2006 11:40 PM
Patrick
Many thanks, i wasn't sure that this way the way it worked or not. Couldnt seem to find a answer in any docs i managed to locate.
So .1 on in inside would not always be .1 on the outside or internet ? that helps me alot, thanks
Regards
Stu
03-15-2006 04:01 AM
i did apply static (inside,dmz) 192.168.1.0 192.168.1.0 netmask 255.255.255.0.
with this static statement, the translation is actually following the last octet.
e.g.
192.168.1.51 will also be translated to .51.
although both the subnet are the same (i.e. really disable natting), however i believe the same logic apply to your scenario as well.
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