04-12-2013 03:17 AM - edited 03-01-2019 05:40 PM
Hello
i have two routers connected via gigabet interface . I have assinged 2 ips 2405:8a00:000a:0003:0000:0000:0000:0010 &
2405:8a00:000a:0003:0000:0000:0000:009 /126 . but these ips are not pinging to each other . pls suggest where i am worng .
04-12-2013 03:52 AM
They can't ping because they are not on the same subnet.
NOTE: I'm assuming the second address you supplied ends in '0009' not '009' as in your post, although leading zero's don't really matter.
Remember IPv6 addresses are in hex, so:
HEX = Decimal
0009 = 9
0010 = 16
What you really want is:
2405:8a00:000a:0003:0000:0000:0000:0009 /126
2405:8a00:000a:0003:0000:0000:0000:000a /126
cheers.
04-12-2013 05:59 AM
Thanks michale ...
it was a confusion during subnetting...
Thanks a lot
04-12-2013 03:53 AM
Hi Satyendra,
I think you are trying to use 2 IPs .9 and .10 of your /126 subnet. But in your address (2405:8a00:000a:0003:0000:0000:0000:0010 - this becomes subnet router anycast address) the last octet is : 0000 0000 0001 0000 which not .10 equivalent. I think you were looking to give 2405:8a00:000a:0003:0000:0000:0000:000A under the interface
So try giving 2405:8a00:000a:0003:0000:0000:0000:000A, and let us know if that works.
Regards,
Ranganath (Cisco)
04-12-2013 07:12 AM
Hello
I am planning to assign IPv6 addresses to my 20 servesr statically . My ipv6 subnet is
fdd2:1fb0:0d7e:3939::/64 and servers is dual stack .
my 15 IPs are :
fdd2:1fb0:0d7e:3939::1
fdd2:1fb0:0d7e:3939::2
fdd2:1fb0:0d7e:3939::3
fdd2:1fb0:0d7e:3939::4
fdd2:1fb0:0d7e:3939::5
fdd2:1fb0:0d7e:3939::6
fdd2:1fb0:0d7e:3939::7
fdd2:1fb0:0d7e:3939::8
fdd2:1fb0:0d7e:3939::9
fdd2:1fb0:0d7e:3939::a
fdd2:1fb0:0d7e:3939::b
fdd2:1fb0:0d7e:3939::c
fdd2:1fb0:0d7e:3939::d
fdd2:1fb0:0d7e:3939::e
fdd2:1fb0:0d7e:3939::f
what will be the next 5 ips and how i will calculate ? pls help and tell the procedure addressing .
04-12-2013 07:53 AM
The ipv6 address is in hexadecimal format, so the next 5 addresses would be:
fdd2:1fb0:0d7e:3939::10,11,12,13,14
Hope this helps
04-17-2013 12:48 AM
Hello Harold
same i have given to the firtst 1---15 serves a a,b,c,d,e,f , but my question is what IPv6 address I have to Assign to 16th to 20 th servers .
04-17-2013 03:45 AM
Hi Satyendra,
So given that the IPv6 address is in hex format, the first 15 servers would be addressed from 1 to f as you mentioned. The next number in the sequence is then 10 in hexadecimal, which means 16 in decimal. The following numbers would be hex 11 (decimal 17), hex 12 (decimal 18), hex 13 (decimal 19) and hex 14 (decimal 20).
Hope this helps
04-17-2013 07:32 PM
hello harold ...
could you explain in details .... how to calculate ?
04-18-2013 05:45 AM
Hi Satyendra,
The hexadecimal system goes from 0 to F and just like the decimal system once you reach F, you increment the next digit and reset the current one to zero as follow:
Hex: 0,1,2,3,4,5,6,7,8,9,a,b,c,d,e,f,10,11,12,13,14,15,16,17,18,19,1a,1b,1c,1d,1e,1f,20,21,22,23,24,25,26,27,28,29,2a,2b,
2c,2d,2e,2f,30,31,32,33,34,35,36,37,38,39,3a,3b,3c,3d,3e,3f,40,41,42,43,44,45,46,47,48,49,4a,4b,4c,4d,4e,4f,50,51,
52,53,54,55,56,57,58,59,5a,5b,5c,5d,5e,5f,60................f0,f1,f2,f3,f4,f5,f6,f7,f8,f9,fa,fb,fc,fd,fe,ff,100,101,102,103.......
Hope this helps
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