Alain provides a very easy and effective solution which is to start in a different /24 network. And this would certainly work. But I sense that Roman may be looking for a solution that would put both subnets into the same /24.
If that is the case then Roman needs to think through the question of what subnets are available in a /27 and which one are already used and which ones are available. A /27 uses a mask of 255.255.255.224 and the subnets and address ranges are as follows
subnet address range
192.168.1.0 192.168.1.1 through 192.168.1.31
192.168.1.32 192.168.1.33 through 192.168.1.63
192.168.1.64 192.168.1.65 through 192.168.1.95
192.168.1.96 192.168.1.97 through 192.168.1.127
192.168.1.128 192.168.1.120 through 192.168.1.159
192.168.1.160 192.168.1.161 through 192.168.1.191
192.168.1.192 192.168.1.193 through 192.168.1.223
192.168.1.224 192.168.1.225 through 192.168.1.255
Assignment of 192.168.1.1 as a /30 makes the first subnet used. But any of the other subnets could be available for use.
Perhaps the most logical thing would be to assign 192.168.1.32/27 as the subnet for the LAN since it is the next available subnet.
HTH
Rick
HTH
Rick
