Hello Brian-
You can apply 2 different NAT statements, yes.
The way it works:
1.) A client sends a SYN into a vlan where the vip is applied as a service-policy input.
2.) The ACE matches the SYN to the class in question, the loadbalance policy is checked, and eventually a server in the associated serverfarm is chosen.
3.) ACE prepares to forward the SYN out of the appropriate VLAN based on the route table.
4.) Before the packet leaves, if the packet will egress either vlan 7 or 741, the the packet would be source NATted by the group number mentioned in the statement. This occurs because the "vlan 7" and "vlan 741" in the NAT statements under the class are filters. If the destination matches either vlan, then the nat group for that statement is used.
i.e.
rserver host server_1
ip address 10.0.0.10
inservice
rserver host server_2
ip address 172.16.35.60
inservice
serverfarm host SF_1
rserver server_1
inservice
class-map match-any VIP_80
2 match virtual-address 172.16.35.80 tcp eq 80
policy map type loadbalance first-match LB
class class-default
serverfarm SF_1
policy map multi-match X
class VIP_80
loadbalance policy LB
loadbalance vip inservice
nat dynamic 5 vlan 7
nat dynamic 7 vlan 741
interface vlan 7
ip address 172.16.35.2 255.255.255.0
nat 5 172.16.35.100 172.16.35.100 netmask 255.255.255.0 pat
service-policy input X
Interface vlan 741
ip address 10.0.0.2 255.255.255.0
nat 7 10.0.0.100 10.0.0.100 netmask 255.255.255.0 pat
service-policy input X
If a packet comes into either vlan destine to 172.16.35.80 on port 80, it will be balanced to either 10.0.0.10 or 172.16.35.60. If 10.0.0.10 was chosen, then natpool 7 under vlan 741 would be used because 10.0.0.10 is layer 2 adjacent to vlan 741. If 172.16.35.60 was chosen, then natpool 5 would be chosen because that server is layer 2 adjacent to vlan 7.
Regards,
Chris Higgins
