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How to capture packets on ip communicator using wireshark

fgramos01
Level 1
Level 1

Hi. I'm trying to capture packets while i am engage to a call using my ip communicator to other site using their ip phones using wireshark. I already tried the capture on lan interface. 

7 Replies 7

Terry Cheema
VIP Alumni
VIP Alumni

1) Launch wireshark - Go to list of available interfaces.

2) Select the interface you are connected to - You should be able to see traffic on that interface.

3) Click start - it should start capturing everything

4) You can filter the sccp traffic by typing skinny in the filter

5) You can filter the media by typing rtp in the filter

6) you can use various other filters source, destination, ip address etc.

-Terry

Please rate all helpful posts

Re-read your post looks like - not sure, you may be after port spanning?

If i am connected to the LAN is right i should choose lan interface on wireshark? And is there something i should enable on the phone configuration to capture the packets? Our main issue is we are having a one way audio when we are recieving calls from other branches of our office from other regions. That's why we want to capture the packets.

If you run wireshark on your PC and you are connected by ethernet cable and you start capturing the packets on LAN interface - it will capture all packets in/out your PC NIC. You can further filter the traffic by applying the filters.

Hi. Thanks. What filter should i apply so i will only see the packets coming from my ip communicator?

If you are using SCCP type skinny, if you are using SIP type sip in filter. This will filter the signalling. You can check in cucm if your CIPC is registered as SCCP or SIP end point.

To filter media - type in rtp.

For more filters based on ip addresses etc. : https://wiki.wireshark.org/DisplayFilters

-Terry

Please rate all helpful posts

Hi thank you very much for the info. I have another question. How am i going to do a traceroute going to cucm and the ip address of the ip phone of the party i am engaged with? Thanks again