0033:4002:2232:0016::/62

[JoshGarmonCiscoCCNA]

How is this address in the '0014' subnet?

Also, how would I write out 0016 in terms of the subnets?

0016 = 0000 0000 0001 01/ 10 <<<< with these 2 bits left over

how do I write out the 4 available subnets? what do they look like?

[Michael Vincent]

Think of it this way:

How is 172.16.10.6 /30 in the 172.16.10.4 /30 subnet?

172.16.10.4 /30

172.16.10.5 /30

172.16.10.6 /30 <---

172.16.10.7 /30

You've done your subnetting in your question.  The last nibble "6" is comprised of bits 60 - 63 in an IPv6 address.  A mask of /62 leaves the last 2 bits (62, 63) for subnet.  So:

nibble = bits 60, 61 | bits 62, 63

4 = 01 | 00

5 = 01 | 01

6 = 01 | 10 <---

7 = 01 | 11

Make sense?