11-17-2017 10:40 PM - edited 03-01-2019 05:54 PM
Could anyone help me with this? I don't know why but Ipv6 makes me sick...
You work for an ISP. The American Registry for Internet Numbers has given you the 2001:0db8:8/34 Ip address block. You need to figure out how many /48 blocks you can assign to your customers.
I know that subneting is the same like we do in Ipv4 however I have difficulties to get this.
Thanks in advance
Solved! Go to Solution.
11-19-2017 10:53 PM
Hi Patrick,
The simple answer is 16384. Technically, you would have 14 bits (/48 - /34), which would give you 16,384 /48. The more difficult answer would be to figure out your IPv6 addressing plan and derive this number.
IPv6 Addressing White Paper:
https://www.cisco.com/c/dam/en_us/solutions/industries/docs/gov/IPv6_WP.pdf
Regards,
11-19-2017 10:53 PM
Hi Patrick,
The simple answer is 16384. Technically, you would have 14 bits (/48 - /34), which would give you 16,384 /48. The more difficult answer would be to figure out your IPv6 addressing plan and derive this number.
IPv6 Addressing White Paper:
https://www.cisco.com/c/dam/en_us/solutions/industries/docs/gov/IPv6_WP.pdf
Regards,
11-21-2017 11:38 AM
11-22-2017 05:44 PM - edited 11-22-2017 05:44 PM
Dear Harold,
Could you please answer my second question regarding IPv6. I couldn't find any differences between those 2 commands:
ipv6 enable
ipv6 address autoconfig
Both of them use link-local address.
11-23-2017 11:10 AM
"ipv6 enable" enables ipv6 on the interface and assigns a link local address using the EUI procedure.
"ipv6 address autoconfig" does the same as "ipv6 enable", but also causes the router to listen to router advertisement coming from the local subnet and to autoconfigure using the Stateless Address Auto Configuration (SLAAC) process.
Regards,
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