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Understanding IPv6 Address from RIR

alexloh83
Level 1
Level 1

Hi Folks,


I am very new to IPv6 and having some question need you guys advices as we are planning to integrate IPv6 to our existing network environment.

RIR allocated 2300:1480::/32 to us, but they said the assignment windows is 2300:1480::/48.

So what is the actual subnet to us? we don't quite understand the address assignment. How about 33-47 bits, it is belong to me or belong to RIR?

(Actual IPv6 address has been removed/modified)



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6 Replies 6

sean_evershed
Level 7
Level 7

You can carve up the block /32 as you see fit.

However talk to your ISP concerning their policies on Internet IPv6 routing.

The longest block that the ISPs in my region will accept from their customers is a /48.

Also have a read of the following RFC

http://tools.ietf.org/html/rfc6177

Don't forget to rate helpful posts.

alexloh83
Level 1
Level 1

Hi Sean,


Further clarification with APNIC, this is their reply....

Does it meant, bit /33-47 is my main subnet And /48-/63 id customer's subnet and /64 is interface id or host in generally?

+++++
For your own infrastructure, you can assign the IP as per your
requirement. For your customers, you can only assign up to /48. If you
need to assign more then /48 to your customers, you need to submit your
APNIC second opinion request.
+++++



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Here is a good starting place for the technicalities of IPv6 subnetting:

https://supportforums.cisco.com/docs/DOC-17232

There is also excellent reference material on the Cisco Live 365 web site

You forgot to mention that you ARE an ISP

Wouter Prins
Level 1
Level 1

The assignment window is what you are allowed to give to your customers without permission from your RIR.

IPv6 is a 128 bit address, while IPv4 is a 32 bit address.

With IPv6 Global Unicast addresses, the first 48 bits is the routing prefix, and the 16 bits after that, can be used to subnet your block out into multiple networks. The last 64 bits are obviously used for the Interface-ID.

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