04-25-2007 06:20 PM
question 1. In a block address, we know the IP address of one host is 182.44.82.16/26. What are the first address (network address) and the last address (limited broadcast address) in this block?
question 2. An organization is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets.
a. Find the subnet mask.
b. Find the number of addresses in each subnet.
c. Find the first and last addresses in subnet 1.
d. Find the first and last addresses in subnet 1024.
Solved! Go to Solution.
04-25-2007 10:55 PM
Hi Eric,
Answer 1)
182.44.82.0 is the subnet address
182.44.82.63 is the broadcast address
Answer 2)
a) 255.255.255.192 will be the subnet mask
b) 62 valid addresses can exist in each subnet
c) First address in subnet 1 will be 130.56.0.1 and last address is sibnet 1 will be 130.56.0.62
d) First address is 1024 subnet will be 130.56.255.193 and last address in 1024 subnet will be 130.56.255.254
HTH
Ankur
*Pls rate helpfull post
04-25-2007 10:55 PM
Hi Eric,
Answer 1)
182.44.82.0 is the subnet address
182.44.82.63 is the broadcast address
Answer 2)
a) 255.255.255.192 will be the subnet mask
b) 62 valid addresses can exist in each subnet
c) First address in subnet 1 will be 130.56.0.1 and last address is sibnet 1 will be 130.56.0.62
d) First address is 1024 subnet will be 130.56.255.193 and last address in 1024 subnet will be 130.56.255.254
HTH
Ankur
*Pls rate helpfull post
04-26-2007 08:29 AM
Thanks so much!
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