01-06-2005 06:09 AM - edited 03-02-2019 08:54 PM
Can someone explain the significance of the available bandwidth under the show interface serial
Serial0/1 is up, line protocol is up
Hardware is GT96K Serial
Description: WAN Link to Exeter
Interface is unnumbered. Using address of FastEthernet0/0 (172.16.6.234)
MTU 1500 bytes, BW 2048 Kbit, DLY 20000 usec,
reliability 255/255, txload 25/255, rxload 5/255
Encapsulation PPP, LCP Open
Open: CDPCP, IPCP, loopback not set
Last input 00:00:00, output 00:00:03, output hang never
Last clearing of "show interface" counters 7w4d
Input queue: 0/75/0/0 (size/max/drops/flushes); Total output drops: 5120
Queueing strategy: weighted fair
Output queue: 0/1000/64/5120 (size/max total/threshold/drops)
Conversations 0/25/256 (active/max active/max total)
Reserved Conversations 1/1 (allocated/max allocated)
Available Bandwidth 736 kilobits/sec
5 minute input rate 48000 bits/sec, 32 packets/sec
5 minute output rate 208000 bits/sec, 41 packets/sec
133028777 packets input, 417742004 bytes, 0 no buffer
Received 0 broadcasts, 0 runts, 0 giants, 0 throttles
1 input errors, 1 CRC, 0 frame, 0 overrun, 0 ignored, 1 abort
93537251 packets output, 3276594573 bytes, 0 underruns
0 output errors, 0 collisions, 34 interface resets
0 output buffer failures, 0 output buffers swapped out
0 carrier transitions
DCD=up DSR=up DTR=up RTS=up CTS=up
I have configured the bandwidth command to be 2048 which you can see at the top.However the available bandwidth reads 736k.Why is this so low?Does this mean i am only using 736k
Here is a sh run aswell.
sh run
!
!
isdn switch-type primary-net5
voice class h323 1
h225 timeout tcp establish 3
!
!!
controller E1 1/0
pri-group timeslots 1-31
!
controller E1 1/1
pri-group timeslots 1-31
!
class-map match-all voice-signaling
match access-group 103
class-map match-all voice-traffic
match access-group 102
!
!
policy-map voice-policy2
class voice-traffic
priority 768
class voice-signaling
bandwidth 32
class class-default
fair-queue
policy-map voice-policy1
class voice-traffic
priority 768
class voice-signaling
bandwidth 32
class class-default
fair-queue
!
!
!
!
!
interface FastEthernet0/0
ip address 172.16.6.234 255.255.0.0
speed 100
full-duplex
h323-gateway voip interface
h323-gateway voip bind srcaddr 172.16.6.234
!
interface FastEthernet0/0.10
description voice vlan
encapsulation dot1Q 10
ip address 10.10.0.1 255.255.0.0
ip helper-address 172.16.6.247
!
interface Serial0/0
description WAN Link to Bodmin
bandwidth 2048
ip unnumbered FastEthernet0/0
service-policy output voice-policy1
encapsulation ppp
!
interface FastEthernet0/1
no ip address
shutdown
duplex auto
speed auto
!
interface Serial0/1
description WAN Link to Exeter
bandwidth 2048
ip unnumbered FastEthernet0/0
service-policy output voice-policy2
encapsulation ppp
invert txclock
!
interface Serial1/0:15
no ip address
no logging event link-status
isdn switch-type primary-net5
isdn incoming-voice voice
no cdp enable
!
interface Serial1/1:15
no ip address
no logging event link-status
isdn switch-type primary-net5
isdn incoming-voice voice
no cdp enable
!
router eigrp 1
network 10.0.0.0
network 172.16.0.0
auto-summary
!
no ip http server
ip classless
ip route 0.0.0.0 0.0.0.0 172.16.1.254
!
!
!
access-list 102 permit udp any any range 16384 32767
access-list 103 permit tcp any eq 1720 any
access-list 103 permit tcp any any eq 1720
access-list 103 permit tcp any any eq 2633
access-list 103 permit tcp any any range 2000 2002
!
01-06-2005 07:20 AM
The bandwidth statement is an administratively settable parameter and is used to determine such things as cost, utilization, etc. The default is 2048 and can be set to the port speed of the circuit (i.e. 512). This is useful if you have a management platform that provides bandwidth utilization numbers.
01-06-2005 07:37 AM
Actually the 'available bandwidth' shown in your show interface commands actually states how much bandwidth is free for that interface. Automatically it takes away 25% for routing protocol traffic, which is your case is 512k. Plus because you have a policy setup for it it takes away the bandwidth you have set up for it which is 768 and 32. You add that together and subtract from 2048 and you get 736. Of course this doesn't mean that you only have 736k left in resourses, it just means that is the amount left that you could apply freely if everything was saturatued. The 'load' is what you want to use to determine actually bandwidth usuage.
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