08-05-2004 12:50 AM - edited 03-02-2019 05:32 PM
Hi can someone please advise on how to verify if a router has sufficient memory to take a full internet routing table.
I know you need at least 128M RAM, but when i do a " show version " i am unsure how to interpret all the different memory figures.
Thanks
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08-05-2004 11:54 PM
Hi,
You will find similar kind of string in ur sh version command as follows.
"cisco 7206VXR (NPE400) processor with 245760K/16384K bytes of memory."
Now,
245760K + 16384K= 262144K
RAM capacity = 262144K/1024 = 256M
so the RAM is 256MB.
Hope this helps.
Amit
08-06-2004 07:02 AM
Memory is measured in bytes, Kilobytes or Megabytes (can use gigabytes too)
1 Kilobyte = 1024 Bytes.
1 Megabyte = 1024 Kilobytes.
Now the number 245760K/16384K = 245760KB+16384KB= 262144KB. The value is in Kilobytes. To convert this into Megabytes, you need to divide this number by 1024. (see above conversion table)
So 262144 KB = 262144/1024 = 256MB.
Hope thats clear.
08-05-2004 01:15 AM
Hello,
the memory consumption by BGP routes depends on the number of attributes such as multi-path support, soft reconfiguration, number of peers, and AS_PATH.
You might want to check this document, it talks in detail about the memory consumption of BGP:
Achieve Optimal Routing and Reduce BGP Memory Consumption
http://www.cisco.com/en/US/tech/tk365/tk80/technologies_tech_note09186a0080094a83.shtml
HTH,
GP
08-05-2004 02:08 AM
Thanks, the document looks good. Can you help with the interpretation of the show version command to verify how much RAM is in a router.
08-05-2004 11:54 PM
Hi,
You will find similar kind of string in ur sh version command as follows.
"cisco 7206VXR (NPE400) processor with 245760K/16384K bytes of memory."
Now,
245760K + 16384K= 262144K
RAM capacity = 262144K/1024 = 256M
so the RAM is 256MB.
Hope this helps.
Amit
08-06-2004 04:57 AM
I have seen a Catalyst 6509 with MSFC and 128MB take the full BGP route table; but CEF ended up being disabled because the box was short on memory.
It might be different with a router and 128MB memory, but I think you should consider 256MB as the minimum for full BGP tables these days.
08-06-2004 06:55 AM
Hi akshri,
Thanks for the reply. Can you also tell me why you divided by 1024 to get the RAM capacity. Where did you get the 1024 from.
08-06-2004 07:02 AM
Memory is measured in bytes, Kilobytes or Megabytes (can use gigabytes too)
1 Kilobyte = 1024 Bytes.
1 Megabyte = 1024 Kilobytes.
Now the number 245760K/16384K = 245760KB+16384KB= 262144KB. The value is in Kilobytes. To convert this into Megabytes, you need to divide this number by 1024. (see above conversion table)
So 262144 KB = 262144/1024 = 256MB.
Hope thats clear.
08-06-2004 11:40 AM
Ver clear, thanks for the info.
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