I have been going through the config-register and I know the following to be true:
0x210X = 9600 baud
0x212X = 19200 baud
0x312X = 57600 baud
0xXXX0 = ROM
0xXXX1 = Bootstrap
0xXXX2 = Normal
The problem is the ignore value of 0x2142.
My question is "Does anyone know why it is 0x2142?" If 2 is normal NVRAM then does that mean that the prefix of 0x214X is the ignore value? What is special about it? I am just really curious about how this value was selected to be the ignore value. If anyone knows of any resources about config-register values and how they relate please let me know.
Solved! Go to Solution.
0xXX2X = bit 5 set = 19200
0xX8XX = bit 11 set = 4800
0x1XXX = bit 12 set = 1200
When all bits are cleared (0) it is the default rate of 9600.
Someone just replied to another post on another site.
The value of 0xXX4X is the ignore NVRAM Value.
here is the link i was looking for: