06-13-2012 10:53 PM - edited 03-04-2019 04:40 PM
Hello All,
Have a question on the EIGRP traffic distribution count. Is there a possibility to perform the traffic distribution in 5:2 ? Below is the calculation to perform a 5:1 ratio distribution (Diagram is attached for the setup).
Note : Using only delay to perform the composite metric calculation
Path via R2 from R1 to reach Loopback on R4
Metric = 256*[sum of delay/10]
=256*[10+10+500]
=256*520
=133120
Path via R3 from R1 to reach Loopback on R4
=256*2510=642560
So. Path via R2 would be successor & path via R3
As Feasible successor.
Variance = FD of FS/FD of Successor
So, 642560/133120 = 4.82
Variance = 5 (whole number)
Lowest metric (FD of the successor)* 5 = 256 * [delay/10]
So, looking at my metric figures
133120 x 5 = 256 * [delay/10]
665600/256 = delay/10
26000 = delay
Now, to determine the local interface delay (LD), we need to subtract the relative distance delay in order to get the LD.
R3 - R4 has a cumulative delay of 5100.
So, 26000 - 5100 = 20900
Now, by setting the delay value of 2090 on the R1 interface connecting to R3, i would achieve 5:1. What can be done to get 5:2 ?
Thanks
Vivek
Solved! Go to Solution.
06-14-2012 10:08 AM
Hello Vivek,
instead of using the equation
133120 x 5 = 256 * [delay/10]
you would use the following:
133120 x 5/2 = 256 * [delay/10]
you get total delay = 13000
you subtract the known delay components and you get
dx = 13000 - 5100 = 7900
so by setting interface delay to 790 tens of microseconds you should get a 5:2 ratio in the metric values on the two paths
Let's verify:
790+10+500 = 1300
on the other path you have
10+10+500 = 520
1300 /520 = 2,5 = 5/2
Hope to help
Giuseppe
06-14-2012 05:33 AM
Interesting,I am also looking for this solution..
-bava
06-14-2012 10:08 AM
Hello Vivek,
instead of using the equation
133120 x 5 = 256 * [delay/10]
you would use the following:
133120 x 5/2 = 256 * [delay/10]
you get total delay = 13000
you subtract the known delay components and you get
dx = 13000 - 5100 = 7900
so by setting interface delay to 790 tens of microseconds you should get a 5:2 ratio in the metric values on the two paths
Let's verify:
790+10+500 = 1300
on the other path you have
10+10+500 = 520
1300 /520 = 2,5 = 5/2
Hope to help
Giuseppe
06-14-2012 07:16 PM
Hi Giuseppe
This was very helpful. I have been struggling on the math for quite a long time on this. I will test this in my lab tonight & update the post.
Again, a great help !!
Regards
Vivek
06-14-2012 11:16 PM
Execellent Giuseppe...!! Thanks for the post Vivek
Discover and save your favorite ideas. Come back to expert answers, step-by-step guides, recent topics, and more.
New here? Get started with these tips. How to use Community New member guide