10-01-2016 02:53 AM - edited 03-08-2019 07:38 AM
I've got some practical exercise for the upcoming mid term exam about assigning IP's to PC's and testing connectivity between those devices. The problem is, I'm not really sure how the IP's on the routers' serial interface are calculated. The IP's for the PC are working flawlessly, but the IP's assigned to the serial interfaces won't work.
The attached image is only a part of the network for the exercise, so it only contains the routers I'm currently working on. Every router is connected to a single switch and they each connect to 500 users and 100 users for router0, 150 users for router1, 30 users for router2, and 300 users and 1 server for router3.
I know how to calculate the IP address for the PC, I just need to know how to calculate/determine the IP for the routers' serial interfaces. The routing has been done before but the config tab is locked so I can't see the routes but I have to assign the exact same address to the correct interfaces to work. The rules for the IP address are: router IP is the last IP, PC IP for every network is the second IP, server IP is the third from the last IP, the sum of the router number is the order of the network, the router IP is ascending according to the router number.
10-01-2016 05:18 AM
Hello,
the easiest way to understand the addressing range requirements as described by you is to use an online IP Subnet calculator, such as the one below. An example: if your PC has IP address 192.168.1.2/24 (which would be the second address in that range), your router's IP address would be 192.168.1.254/24 (last in range), and the server's IP address would be 192.168.1.252/24 (third from last).
http://www.subnet-calculator.com/
HTH
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