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acl creating

jimgurley
Level 1
Level 1

I'm struggling to make a tweak to our ASA5505.  A consultant built the original config, and he's no longer available or interested.

I'm trying to open an outbound TCP port to a single IP address, and I just can't find the formula.  There aren't any examples in the existing config.  I want the entry to be in the second entry.  I'm typing

"access-list inside_out extended line 2 permit tcp any host bozo.245.22.71.114 eq 8074"

and I get a response of "invalid input at "^"" where the "^" it at the right margin.   I've tried adding an "out" on the end with no change to the result. bozo... is listed in the name section, although I added it.  Do you have to "execute" to have a running-config take effect?  I struggled last time I did a similar task and gave up and opened an IP without respect to port, which seems an unnecessary risk.

1 Accepted Solution

Accepted Solutions

Julio E. Moisa
VIP Alumni
VIP Alumni

Hi

Try with:

 

access-list inside_out  line 2 extended permit tcp any host bozo.245.22.71.114 eq 8074

 

I have not used words along with an IP address before, so it should be: 

 

access-list inside_out  line 2 extended permit tcp any host 245.22.71.114 eq 8074

 




>> Marcar como útil o contestado, si la respuesta resolvió la duda, esto ayuda a futuras consultas de otros miembros de la comunidad. <<

View solution in original post

2 Replies 2

Julio E. Moisa
VIP Alumni
VIP Alumni

Hi

Try with:

 

access-list inside_out  line 2 extended permit tcp any host bozo.245.22.71.114 eq 8074

 

I have not used words along with an IP address before, so it should be: 

 

access-list inside_out  line 2 extended permit tcp any host 245.22.71.114 eq 8074

 




>> Marcar como útil o contestado, si la respuesta resolvió la duda, esto ayuda a futuras consultas de otros miembros de la comunidad. <<

Thx.  The order of line/extended fixed it.  So much for my Network Professional's Library guidebook!  Should have been obvious from the show version, but I trusted the book.