Hi, someone post this lab on facebook.i try start to make this work and got many confusions.here is my first one
If you look at the topology Branch1 router has this route in its route table
Branch1#sh ip route eigrp
193.10.24.0/30 is subnetted, 2 subnets
D 193.10.24.0 [90/2681856] via 193.10.25.1, 02:30:24, Serial1/0.1
D 193.10.24.4 [90/2681856] via 193.10.26.1, 02:29:44, Serial1/0.2
10.0.0.0/24 is subnetted, 3 subnets
D 10.1.3.0 [90/2684416] via 193.10.26.1, 00:16:20, Serial1/0.2
[90/2684416] via 193.10.25.1, 00:16:20, Serial1/0.1
D 10.0.0.0 [90/2172416] via 193.10.26.1, 02:29:46, Serial1/0.2
[90/2172416] via 193.10.25.1, 02:29:46, Serial1/0.1
and has neighbour with
Branch1#sh ip eigrp neighbors
IP-EIGRP neighbors for process 15
H Address Interface Hold Uptime SRTT RTO Q Seq
(sec) (ms) Cnt Num
1 193.10.26.1 Se1/0.2 131 12:33:14 284 1704 0 63
0 193.10.25.1 Se1/0.1 167 12:33:41 210 1260 0 59
{Wan1 interfaces details:-
interface FastEthernet0/0
ip address 10.0.0.10 255.255.255.0
duplex full
!
interface Serial1/0
no ip address
encapsulation frame-relay
serial restart-delay 0
!
interface Serial1/0.1 multipoint
ip address 193.10.25.1 255.255.255.0
frame-relay map ip 193.10.25.20 102 broadcast
frame-relay map ip 193.10.25.10 101 broadcast
!
interface Serial1/0.2 point-to-point
ip address 193.10.24.1 255.255.255.252
frame-relay interface-dlci 103
Wan2
interface FastEthernet0/0
ip address 10.0.0.20 255.255.255.0
duplex full
!
interface Serial1/0
no ip address
encapsulation frame-relay
serial restart-delay 0
!
interface Serial1/0.1 multipoint
ip address 193.10.26.1 255.255.255.0
frame-relay map ip 193.10.26.20 202 broadcast
frame-relay map ip 193.10.26.10 201 broadcast
!
interface Serial1/0.2 point-to-point
ip address 193.10.24.5 255.255.255.252
frame-relay interface-dlci 203
i want to know how the branch1 router get the 10.1.3.0 route, where wan1 and wan 2 serial interfaces are in split horizon ON.Thanks in advance
Accepted Solutions
Diagnose the Split Horizon at which points it could be?
For Tree 1.
R8 is the point where spilit horizon will be in effect
For Tree 2:
R8 is the point where spilit horizon will be in effect
Design Issue in Tree 2:
Interfaces serial.2 is connecting to R7 and R9 and configured as P2P interface which is wrong as each router is connecting to more than one router it should be P2M.
For this question that is not taking any part so we ignore it for moment.
For Tree 3:
R9 is the point where spilit horizon will be in effect
Lets write the routing table for HUBS for each tree.
WAN 1:
it should have
10.1.1.0/24
10.1.2.0/24
10.1.3.0/24
WAN 2
10.1.1.0/24
10.1.2.0/24
10.1.3.0/24
Lets see with Split Horizon on at HUB spokes for each tree which routes they will have.
Branch 1:
no route from Tree 1 spokes (branch 2) beacuse HUB is on with Split horizon as it is connecting serial.1 to branch 1 and branch 2.
10.1.3.0/24 from Tree 2 as branch 1 is on serial.1 of HUB (R8) and R7 is on serial.2 so no split horizon is ineffect at this interface.
10.1.3.0/24 from Tree 3 as branch 1 is on serial.1 of HUB (R9) and R7 is on serial.2 so no split horizon is ineffect at this interface.
Branch 2:
no route from Tree 1 spokes (branch 1) beacuse HUB is on with Split horizon as it is connecting serial.1 to branch 1 and branch 2.
10.1.3.0/24 from Tree 2 as branch 2 is on serial.1 of HUB (R8) and R7 is on serial.2 so no split horizon is ineffect at this interface.
10.1.3.0/24 from Tree 3 as branch 2 is on serial.1 of HUB (R9) and R7 is on serial.2 so no split horizon is ineffect at this interface.
Calculate for others now hope you got your concept cleared.
Disable the split horizon as per the diagram for each tree your routing tables will be completed
Regards
Waqas Younas
CCIEx2 #27815 (RnS & SP)
Diagnose the Split Horizon at which points it could be?
For Tree 1.
R8 is the point where spilit horizon will be in effect
For Tree 2:
R8 is the point where spilit horizon will be in effect
Design Issue in Tree 2:
Interfaces serial.2 is connecting to R7 and R9 and configured as P2P interface which is wrong as each router is connecting to more than one router it should be P2M.
For this question that is not taking any part so we ignore it for moment.
For Tree 3:
R9 is the point where spilit horizon will be in effect
Lets write the routing table for HUBS for each tree.
WAN 1:
it should have
10.1.1.0/24
10.1.2.0/24
10.1.3.0/24
WAN 2
10.1.1.0/24
10.1.2.0/24
10.1.3.0/24
Lets see with Split Horizon on at HUB spokes for each tree which routes they will have.
Branch 1:
no route from Tree 1 spokes (branch 2) beacuse HUB is on with Split horizon as it is connecting serial.1 to branch 1 and branch 2.
10.1.3.0/24 from Tree 2 as branch 1 is on serial.1 of HUB (R8) and R7 is on serial.2 so no split horizon is ineffect at this interface.
10.1.3.0/24 from Tree 3 as branch 1 is on serial.1 of HUB (R9) and R7 is on serial.2 so no split horizon is ineffect at this interface.
Branch 2:
no route from Tree 1 spokes (branch 1) beacuse HUB is on with Split horizon as it is connecting serial.1 to branch 1 and branch 2.
10.1.3.0/24 from Tree 2 as branch 2 is on serial.1 of HUB (R8) and R7 is on serial.2 so no split horizon is ineffect at this interface.
10.1.3.0/24 from Tree 3 as branch 2 is on serial.1 of HUB (R9) and R7 is on serial.2 so no split horizon is ineffect at this interface.
Calculate for others now hope you got your concept cleared.
Disable the split horizon as per the diagram for each tree your routing tables will be completed
Regards
Waqas Younas
CCIEx2 #27815 (RnS & SP)
