In a IOS command line, how can I filter the result of "?"?

[ew6DjDBNs48JaZYu3aiwaCrxvYfm2X]

In a IOS command line, I can use the "include" command to filter piped results.

PC1#show running-config | include inter
interface FastEthernet0/0
interface FastEthernet0/1
interface FastEthernet1/0
interface FastEthernet1/1
PC1#

How can I , or is it possible, to filter the result of the helping information get from "?"? I tried to type the question mark with ctrl+v ? but it doesn't work.

PC1#show ? | include con
         ^
% Invalid input detected at '^' marker.

PC1#

[balaji.bandi]

PC1#show ? | include con

not sure what you trying to achieve, are you looking to show command get output only have con?

[ew6DjDBNs48JaZYu3aiwaCrxvYfm2X]

When I type "show ?", I get the following result:

R1#show ?
  aaa                       Show AAA values
  aal2                      Show commands for AAL2
  access-expression         List access expression
  access-lists              List access lists
  acircuit                  Access circuit info
  ...

R1#show

How can I filter this result and get only the lines that include "con"?

[Christopher Hart]

Hello!

You can invoke the context-sensitive help partway through a phrase to obtain a list of commands matching that phrase. For example:

R1# show con?
  console
  confirm
  ...

I hope this helps - thank you!

-Christopher

[balaji.bandi]

why not use simple show con? will give you more granular output.

[ew6DjDBNs48JaZYu3aiwaCrxvYfm2X]

I know I can use "show con?". I'm just discussing the possibility of filtering the result of "show ?". Is it possible to filter the result of "show con?"?

[balaji.bandi · Accepted solution]

Cisco use (Coding methodology) what is the best used, it all depends on how they write core on C or whatever language they incorporate as IOS.

In Linux, you have many possibilities for what you looking for since that is a full OS