02-22-2008 12:36 PM - edited 03-03-2019 08:50 PM
Hello everybody,
I want to filter all prefixes that have private ASNs in their AS path and I want to achive this via an ip as-path access-list. (neighbor x.x.x.x remove-private-as isn't an option)
What would a regexp have to look like that filters all ASNs from 64512-65535 ?
Regards,
Dirk
Solved! Go to Solution.
02-23-2008 05:22 AM
Dirik
I think this can solve your problem.
ip as-path access-list 1 permit (_64[6-9][0-9][0-9]_|_65[0-9][0-9][0-9]_)
regards
shivlu
02-23-2008 05:22 AM
Dirik
I think this can solve your problem.
ip as-path access-list 1 permit (_64[6-9][0-9][0-9]_|_65[0-9][0-9][0-9]_)
regards
shivlu
02-23-2008 06:10 AM
Hello Shivlu,
Thank you very much for your reply, it's the right approach - it's just missing the range from 64512-64599.
I found this here:
ip as-path access-list 150 permit _(6451[2-9]|645[2-9][0-9]|64[6-9][0-9][0-9])_
ip as-path access-list 150 permit _(65[0-4][0-9][0-9]|655[0-2][0-9]|6553[0-5])_
on http://www.merit.edu/mail.archives/nanog/2003-01/msg00365.html
Kind regards,
Dirk
02-23-2008 06:28 AM
Thanks for sending me the link of good community.
regards
shivlu
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