02-05-2024 10:05 AM
Hi so I have to assing my own Ip address to all these devices and connections based on my birthday, the instructions were however not clear, what got me confused are these statements, "First Stub(leaf) Ethernet Segment for each Router (Network that is connected only to a single router port) R1 f0/0 = 212.7.1.1
R2 f0/0 = 212.7.2.2
R3 f0/0 = 212.7.3.3
R4 f0/0 = 212.7.4.4
R5 f0/0 = 212.7.5.5
and
The second Stub(leaf) Ethernet Segment for each Router (Network that is connected only to a single router port) if such
network exist in the topology
R1 = 212.7.10.1
R2 = 212.7.20.2
R3 = 212.7.30.3
R4 = 212.7.40.4
R5 = 212.7.50.5
To be precise is the connection from router 5 to pc 5 considered as second stub?
02-05-2024 10:32 AM
Hello,
very difficult to understand what they want indeed. To me it sounds like they want you to think of each PC as a First Stub (leaf), and all the connections between the routers as Second Stub (leaf)...so the connection between R5 and PC5 would be a First Stub...
02-05-2024 10:43 AM
Yes, connection from router 5 to pc 5 considered as second stub; Stub network is a network with one way out of it; like PCs connected directly to router have 1 way out only! Link between 2 routers are usually called point-to-point link, or "slash 30, aka /30.
where is this from? book, class? there should be definition of stub segment;
Regards, ML
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