C3650 Stack Role are Different

[phaneathcisco]

Dear All, 

I have a problem with my Cisco Switch C3650 stack after I added 3rd member into stack, but its role are different as below:

*1      Active          5c83.8f59.0580       15     V02     Ready
2       Standby       5c83.8f2d.4180       14     V02     Ready
3       Member       843d.c69c.a680       13     V03    Ready

Please help to advice me how can I change the 3rd member to Standby role the 2nd one?

Regards, 

Phaneath

[Georg Pauwen]

Hello,

you have to change the priority value of the member switch (currently 13) to 14, and that of the standby switch (currently 14) to 13. Use this command:

switch 2 priority 13

switch 3 priority 14

http://www.cisco.com/c/en/us/td/docs/switches/lan/catalyst3650/software/release/3se/ha_stack_manager/configuration_guide/b_hastck_3se_3650_cg/b_hastck_3se_3650_cg_chapter_010.html#task_1106477

[phaneathcisco]

Hello, 

I think I may confused or what that I need to change role on both switch 2 and 3 to standby role. In stack only one switch can be a standby role. Am I correct?

Regards,

Phaneath

[Georg Pauwen]

Phaneath,

sorry for the confusion. When you change the priority of switch 3 to 14, it becomes the standby switch. Since switch 2, which is currently the standby switch, has the same priority, you need to lower it to 13, it will then become the member switch.

So basically, when you change the priority on both switches, it will look like this:

*1      Active          5c83.8f59.0580       15     V02     Ready
3       Standby       5c83.8f2d.4180       14     V02     Ready
2       Member       843d.c69c.a680       13     V03    Ready

Does that make sense ?

[phaneathcisco]

Hello,

Actually, what I need as below:

*1 Active 5c83.8f59.0580 15 V02 Ready
2 Standby 5c83.8f2d.4180 14 V02 Ready
3 Standby 843d.c69c.a680 13 V03 Ready

Is it possible? But in stack switch standby role can have more than one switch or not? If not, I think I'm confused.

Thanks,

[Georg Pauwen]

Hello,

you can only have one standby switch in the stack.