packet

[trent16]

IP ADDRESS  172.16.20.0/21 100 devices and 192.168.100.0/24 50 devices have to use second address for 3rd subnet 

Leg A

router 172.16.20.1 255.255.255.128

problem is 3rd subnet 192.168.100.193 255.255.255.252

Server 172.16.20.2 IPV4  255.255.255.128 SUBENT  172.16.20.1DEFAULT

Leg B packet

Router 192.168.100.129 255.255.255.192

3 subnet where I get my problem with the over lap 192.168.100.194 255.255.255.252

SERVER 

192.168.100.130 IPV4  255.255.255.192 SUBNET  192.168.100.129 DEFAULT

asking for some help.

The tag on here is wrong

[Georg Pauwen]

Hello,

what exactly is your question ? Which subnets do you need, where is the overlap ? Please clarify.

[trent16]

The 3rd subnet is where it (over laps) where and how I have no clue.

leg A I have on the router 

192.168.100.193 255.255.255.252

and leg  B I have

192.168.100.194 255.255.255.252

[Georg Pauwen]

Hello,

192.168.100.193 255.255.255.252 and 192.168.100.194 255.255.255.252 are the two host addresses in subnet 192.168.100.192/30.

It is unclear what your problem is...

[trent16]

Yes so this is the question for the assignment


- *Leg A*
- 172.16.20.0/21 Device addresses required 100
- VLAN 10
- *Leg B*
- 192.168.100.0/24 Device addresses required 50

And my 3rd sub net "over laps"

[Georg Pauwen]

Hello,

192.168.100.0/24 host a host range of 192.168.100.1 thru 192.168.100.254. So 192.168.100.192/30 is part of that range.

If you need to use 192.168.192.30/30, you need to use e.g. 192.168.100.0/25. This includes the host range 192.168.100.1 thru 192.168.100.126.

[trent16]

Yes 1-126 and my second one is
129-190
Now to my 3rd which changes to a /30 I have 193-194 is the router to router
connection

[Georg Pauwen]

Hello,

192.168.100.128/26 and 192.168.100.192/30 do not overlap.

[trent16]

I dont know what it is .

[Reza Sharifi]

What is your question?

[trent16]

It is not allowing me to input 3rd subnet it is saying it is over lapping

[Reza Sharifi]

You are probably configuring the wrong mask somewhere and that is why you see the over-lapping message.

Can you post the entire config using "sh run"?

HTH

[trent16]

Yes I can give me one moment

[trent16]

LEG_B>en

LEG_B#sh run

Building configuration...

Current configuration : 738 bytes

!

version 12.4

no service timestamps log datetime msec

no service timestamps debug datetime msec

no service password-encryption

!

hostname LEG_B

!

!

!

!

!

!

!

!

ip cef

no ipv6 cef

!

!

!

[trent16]

This is what I have for the subnetting this is my subneting what I have imputed

for LEG A 

172.16.20.0/21 100 devices 

                       Device range         broadcast 

172.16.20.0        1-126                    127

what I put into router 1 LEG A 

ip addr  172.16.20.1  255.255.255.128

no sh

int s0/0/0

ip addr 192.168.100.193 255.255.255.252      3RD SUBNET 

Now for my server on leg A

172.16.20.2 IPV4

255.255.255.128 SUBNET

172.16.20.1 DEFAULT

now for my second subnet for LEG B 

192.168.100.0/24    50 DEVICES

                                DEVICE RANGE      BROADCAST 

192.168.100.128        129-190                   191    

ROUTER LEG B

IP ADDR 192.168.100.129  255.255.255.192

NO SH

INT S0/0/0 192.168.100.194 255.255.255.252    THIS IS WHERE THE " OVER LAP " IS IN MY 3RD SUBNET  

SERVER LEG B

192.168.100.130 IPV4 

255.255.255.192 SUBNET 

192.168.100.129 DEFAULT