Subnetting: Can you prove the following questions?

[silverlookz007]

We have a Class-B network address 172.16.0.0. It is required to subnet this network using CIDR (/19).

Find the answers for following questions?

1. What is the fifth subnet address?

2. What is the broadcast address of the third subnet?

3. What is the valid host range in the sixth subnet?

[Rolf Fischer]

There are many sources about subnetting, e.g. http://www.wikihow.com/Calculate-Network-and-Broadcast-Address .

You even find videos on youtube.

In your example, you have the following network:

172.16/16

Dividing it in 2 subnets of equal size results in:

172.16.0/17 (172.16.0.1 - 172.16.127.254; BC: 172.16.127.255)

172.16.128/17 (172.16.128.1 - 172.16.255.254; BC: 172.16.255.255)

4 subnets of equal size:

172.16.0/18

172.16.64/18

172.16.128/18

172.16.192/18

(...)

If you understand the basic concepts, you'll be able to solve the question yourself in less than 10 minutes.

Good luck,

Rolf

[Mohammed Aswath Ali]

We have a Class-B network address 172.16.0.0. It is required to subnet this network using CIDR (/19).

Find the answers for following questions?

1. What is the fifth subnet address?

Ans  -   172.16.129.0  to  172.16.160.0

2. What is the broadcast address of the third subnet?

Ans  -  172.16.96.255

3. What is the valid host range in the sixth subnet?

Ans - 8190

Kindly correct me if i am wrong

[InayathUlla Sharieff]

Easy way use the ip subnet calculator.

http://www.aboutmyip.com/AboutMyXApp/SubnetCalculator.jsp?ipAddress=72.16.0.0&cidr=19

Regards

Inayath