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Route pattern without pound key

samhopealpha
Level 1
Level 1

Dear everybody,

I have a question about route pattern. here are the requiments

1. local outbound call should be prefix 9 + 8 digits (without # at the end) e.g. 9XXXXXXXX

2. international outbound call should be prefix 9 + 011 + country code + phone number (without # at the end)

3. after finsih dialing, waiting time should not greater than 3 seconds

Therefore, I use 9.! as the route pattern and reduce the inter-digit timeout to 3 seconds.

But some end-users are not satisfied with that, because they said the interdigit timeout is too short for them.

I understand that the # key can represent the signal of finish dialing, however the requirment is to omit # key...

Apart from this is there any other way to fulfill the above requirment?

Thanks in advance

Sam

1 Accepted Solution

Accepted Solutions

Jaime Valencia
Cisco Employee
Cisco Employee

Not really, as long as you have overlapping patterns you'll always face that problem.

With international calls as CUCM doesn't know how many digits you'll dial it's either wait for IDT or press #

Tell them to dial on-hook so that when they go off-hook, the phone will let CUCM that's all the digits he needs to expect and route the call.

HTH

java

if this helps, please rate

www.cisco.com/go/pdihelpdesk

HTH

java

if this helps, please rate

View solution in original post

1 Reply 1

Jaime Valencia
Cisco Employee
Cisco Employee

Not really, as long as you have overlapping patterns you'll always face that problem.

With international calls as CUCM doesn't know how many digits you'll dial it's either wait for IDT or press #

Tell them to dial on-hook so that when they go off-hook, the phone will let CUCM that's all the digits he needs to expect and route the call.

HTH

java

if this helps, please rate

www.cisco.com/go/pdihelpdesk

HTH

java

if this helps, please rate