08-01-2002 10:00 PM - edited 03-02-2019 12:23 AM
I have a 2621 router which links our internal network to two separate ISPs. I have two different internal networks, each needing to exit the router through separate interfaces to the different isps, I want to create a route map which will let me do this. This is what I am trying
interface FastEthernet0/0 (LAN interface that both networks share)
ip add x.x.x.x y.y.y.y
ip policy route-map Tenants
route-map Tenants permit 10
match ip address 20
set inteface FastEthernet0/1 (the interface I want this traffice to exit)
access-list 20 permit x.x.x.z z.z.z.z
This doesn't seem to be working.
Suggestions?
Gerard Forster
08-02-2002 09:16 AM
Gerard,
If your client sources are x.x.x.x y.y.y.y and your acl in your route-map is permitting x.x.x.z z.z.z.z then you might not be satisfying your match condition. I would guess, without seeing your IP addresses that you might have an ACL issue where nothing is matching. "show route-map" should show you your tenants route-map and matches incurred by each permit statement.
Once you get this working you can also use a "set ip next-hop x.x.x.x" where x.x.x.x is the next hop of your ISP. On non point to point type links (Ethernet) this is a better practice then just setting and out bound interface.
Hope this helps,
Don
08-02-2002 10:42 AM
try to use IP extended access list.
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