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iBgp full mess

robtos
Level 1
Level 1

Hello,

Can anybody tell me the equation you use to calculate how many ibgp sessions you need to create a full mess ( with x amount of bgp peers)

Thanks for your help!

1 Accepted Solution

Accepted Solutions

royalblues
Level 10
Level 10

n*(n-1)/2

where n is the number of nodes running BGP

Since this would sometimes result in a large number of IBGP sessions you can implement RR(route reflectors) and confederations.

HTH

Narayan

View solution in original post

4 Replies 4

royalblues
Level 10
Level 10

n*(n-1)/2

where n is the number of nodes running BGP

Since this would sometimes result in a large number of IBGP sessions you can implement RR(route reflectors) and confederations.

HTH

Narayan

That's it...couldn't find it, thanks

devang_etcom
Level 7
Level 7

if you have X amount of BGP Peers then you will have X(X-1)/2 session in your AS

regards

Devang

lloyd_andrew
Level 1
Level 1

The [n(n-1)]/2 is a good general calculation for full mesh. Used to be used a lot before in Frame-Relay when calculating the number of PVC's needed for full mesh.

Just my additional $.02.

-lloyd