OSPF static redistribution
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08-18-2011 07:55 PM - edited 03-04-2019 01:19 PM
I'm trying to redistribute a single static route from my router into my ospf process to propagate to other routers in my network without having to advertise all of my static routes. I am using a route-map to do this, but I'm having a problem. When I do a show ip route xx.xx.xx.61, I see that it is being redistributed (as well as being a static route), but I cannot see it on any neighbor routers as a route. Any insight would be greatly appreciated
ip route xx.xx.xx.61 255.255.255.255 xx.xx.xx.34
ip access-list extended REDIST
permit ip host xx.xx.xx.61 any
route-map REDIST permit 10
match ip address REDIST
set metric 10
metric-type type-1
router ospf xx
redistribute static subnets route-map REDIST
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08-18-2011 09:20 PM
Why are you using an extended ACL?
outer ospf 1
log-adjacency-changes
redistribute static subnets route-map STATIC-TO-OSPF
network 192.168.1.1 0.0.0.0 area 0
!
ip forward-protocol nd
ip route 1.1.1.1 255.255.255.255 Null0
ip route 2.2.2.2 255.255.255.255 Null0
ip route 3.3.3.3 255.255.255.255 Null0
no ip http server
no ip http secure-server
!
!
!
access-list 1 permit 1.1.1.1
!
!
!
route-map STATIC-TO-OSPF permit 10
match ip address 1
set metric 10
set metric-type type-1
on the adjancent router:
Router#sh ip route os
1.0.0.0/32 is subnetted, 1 subnets
O E1 1.1.1.1 [110/11] via 192.168.1.1, 00:00:07, FastEthernet0/0
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08-18-2011 11:47 PM
Hi james,
I just verified that it works with the extended ACL but it should be redistributed as E2 because you missed the set keyword before the metric-type.
Can you do a sh run | s router ospf and sh ip ospf and post output.
Regards.
Alain.
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08-19-2011 02:59 AM
please use the redistribution suggested by Edison because extended ACL it works but you dont need complicate things as it works a bit differently interns of source the network and the destination is considered the source of the route
however simple standard ACL will match the source route with no issues as per the example provided by Edison
HTH
