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/20 subnet question

njnetwork
Level 1
Level 1

Hello all,

I'm trying to answer the following question: 

What is the next subnet ID for the IP address: 172.29.48.0 /20

/20 block size is 4096 addresses (not subtracting 2 here, because we're not calculating hosts)

How do I get from 172.29.48.0 to the next network address of 172.29.52.0? The network blocks are incrementing by 4 in the third octet, but I don't understand why. I've scoured the internet trying to answer this question, and am not finding what I need. Chat GPT was also unhelpful. 

Any clarification would be greatly appreciated.


 

 

2 Accepted Solutions

Accepted Solutions

4096 hosts 
each netework bit give you 255 hosts 
4096/255 host = 16 
that why you see the network-network interval is 16 

View solution in original post

Joseph W. Doherty
Hall of Fame
Hall of Fame

"How do I get from 172.29.48.0 to the next network address of 172.29.52.0?"

You don't, if you're using /20s.  The next network address, for a /20, would be 172.29.64.0.

172.29.52.0/20 is within 172.29.48.0/20, i.e. it's a host address.

BTW, another way to understand the situation, is "watch" the binary values.

A /20 divides the 32 bit IP address as: nnnnnnnn.nnnnnnnn.nnnnhhhh.hhhhhhhh.

In the third octet, the last network bit is the 4th bit, of 8.  I.e. binary 10000 = 16 decimal, which is why you see, in @MHM Cisco World first posting, the 3rd octet jumping by 16s.

"/20 block size is 4096 addresses (not subtracting 2 here, because we're not calculating hosts)"

Yes, that's correct, each /20 contains an IP address range of 4,096 because the largest host number, in binary, is 1111 1111 1111 or 4,065 decimal, plus counting zero, provides 4,096 numbers.

View solution in original post

6 Replies 6

Screenshot (506).png

njnetwork
Level 1
Level 1

Thank you for you response, but this is not helpful. I know how to use a subnet calculator. I'm trying to understand what calculation is used to increment subnets this large. I need the why, not the answer. 

4096 hosts 
each netework bit give you 255 hosts 
4096/255 host = 16 
that why you see the network-network interval is 16 

Joseph W. Doherty
Hall of Fame
Hall of Fame

"How do I get from 172.29.48.0 to the next network address of 172.29.52.0?"

You don't, if you're using /20s.  The next network address, for a /20, would be 172.29.64.0.

172.29.52.0/20 is within 172.29.48.0/20, i.e. it's a host address.

BTW, another way to understand the situation, is "watch" the binary values.

A /20 divides the 32 bit IP address as: nnnnnnnn.nnnnnnnn.nnnnhhhh.hhhhhhhh.

In the third octet, the last network bit is the 4th bit, of 8.  I.e. binary 10000 = 16 decimal, which is why you see, in @MHM Cisco World first posting, the 3rd octet jumping by 16s.

"/20 block size is 4096 addresses (not subtracting 2 here, because we're not calculating hosts)"

Yes, that's correct, each /20 contains an IP address range of 4,096 because the largest host number, in binary, is 1111 1111 1111 or 4,065 decimal, plus counting zero, provides 4,096 numbers.

Thank you! This is super helpful.

You're most welcome.

One of IPv4's mysteries, to me, is why IP addresses are represented as a dot-decimal.  Maybe because it was seen to go well with Classful addressing?

Certainly makes many struggle when you need to use ACLs and/or subnet/supernet.

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