12-12-2012 07:44 PM - edited 03-07-2019 10:34 AM
Hi everybody.
I am getting a little different result than expected in the following example.
|--------f0/0--R1-----s0/0-------------------R2
R1 config :
f0/0 10.10.10.1/8
s0/0 199.199.199.1/24
eigrp 1
network 10.0.0.0
network 199.199.199.0
When R1 sends update about 10.0.0.0/8 to R2 , it should contain bandwidth as 100,000 ( Kb), delay 100 ( 10 tens of microsecond) with f0/0 default values:
bandwidth 100Mbs
Delay on f0/0 1000 u sec
However When I performed the packet capture of the update I found following:
No. Time Source Destination Protocol Length Info
43 84.489000 199.199.199.1 199.199.199.2 EIGRP 70 Update
Frame 43: 70 bytes on wire (560 bits), 70 bytes captured (560 bits)
Cisco HDLC
Internet Protocol Version 4, Src: 199.199.199.1 (199.199.199.1), Dst: 199.199.199.2 (199.199.199.2)
Cisco EIGRP
Version: 2
Opcode: Update (1)
Checksum: 0xcdbe
Flags: 0x00000008
Sequence: 3
Acknowledge: 2
Autonomous System: 1
IP internal route = 10.0.0.0/8
Type: IP internal route (258)
Size: 26
Next Hop: 0.0.0.0 (0.0.0.0)
Delay: 25600
Bandwidth: 256000
MTU: 1500
Hop Count: 0
Reliability: 255
Load: 1
Reserved: 0
Prefix Length: 8
Destination: 10.0.0.0
I appreciate your help.
Solved! Go to Solution.
12-12-2012 07:52 PM
Hi
bandwidth = (10000000/bandwidth(i)) * 256
where bandwidth(i) is the least bandwidth of all outgoing interfaces on the route to the destination network represented in kilobits.
EIGRP uses the following formula to scale the delay:
delay = delay(i) * 256
http://www.cisco.com/en/US/tech/tk365/technologies_white_paper09186a0080094cb7.shtml
Thanks
Raju
12-12-2012 07:52 PM
Hi
bandwidth = (10000000/bandwidth(i)) * 256
where bandwidth(i) is the least bandwidth of all outgoing interfaces on the route to the destination network represented in kilobits.
EIGRP uses the following formula to scale the delay:
delay = delay(i) * 256
http://www.cisco.com/en/US/tech/tk365/technologies_white_paper09186a0080094cb7.shtml
Thanks
Raju
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