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Ip address issue

WEERAKOO69BA
Level 1
Level 1

Hi i have one quiery.If some one assign iIp as follows,

interface Vlan3
ip address 192.168.1.5 255.255.255.248
(7addresses are alowed192.168.1.5-1.12)


interface Vlan4
ip address 192.168.1.42 255.255.255.248
(7 addresses are allowed from 192.168.1.42 -49)

interface Vlan10
ip address 192.168.1.128 255.255.255.128
**127 arredsses are allowed
192.168.1.128 - 254

My question is ,
1)if ip address 192.168.1.253 255.255.255.128
how amny addreses are allowed and what are those???(only 254 or ??)
2)ip address192.168.1.253 255.255.255.0 -If one asign IP for vlan 10,will it clash with other vlans.??

Thanks

7 Replies 7

cadet alain
VIP Alumni
VIP Alumni

Hi,

1)  ip address 192.168.1.253 255.255.255.128

so subnet is 192.168.1.128 and hosts go from 192.168.1.129 to 192.168.1.254 so 127 addresses as the /25 suggests

2)ip address192.168.1.253 255.255.255.0 -If one asign IP for vlan 10,will it clash with other vlans.??

yes it will overlap with other vlans because here addresses go from 192.168.1 .1 to 192.168.1.254.

all masks greater than /24 are subnets of /24

Regards.

Alain.

Don't forget to rate helpful posts.

alain,

Thanks a lot for the reply.That mean it will go from 192.168.1.128 -192.168.1.254

no 192.168.1.253/254 and 1to 125??

Thanks

What do you mean? Can you clarify.

Regards.

Alain.

Don't forget to rate helpful posts.

Thanks

what I asked was,The ip address range will go from 192.168.1.128  to  192.168.1.254.That means the range is not as follows,

192.168.1.253

192.168.1.254

192.168.1.1

192.168.1.2

.192.168.1.3

..

....

...

192.168.1.126

??

If the range goes from .128 to .254 then the addresses are from .129 to .254

Regards.

Alain.

Don't forget to rate helpful posts.

Thanks a lot,

But pls have a look on the folllowing  senario,

if

vlan 10

ip address 192.168.1.12 255.255.255.248

this has 7 ips alright?

are those--192.168.1.13  to 192.168.1.18

OR

192.168.1.12. to 192.168.1.6(back ward)  ????

Thanks

192.168.1.12 255.255.255.248

255-248=8 is subnet increment so the range is 192.168.1.9 to 192.168.1.14 included for IP addresses.

192.168.8 is subnet and 192.168.1.15 is broadcast.

Regards.

Alain.

Don't forget to rate helpful posts.
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