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Beginner

OSI and TCP/IP model

Hi,

I made a table for OSI model and TCP/IP model and diffrent protocols. If you have any additions, comments feel free to reply. There are a lot of protocols out there and these are only few and I want to separate each protocol to its correct layers.

proto.jpg

Any addition or comments will be much appreciated.

Thanks.

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Cisco Employee

OSI and TCP/IP model

Hi Rivan,

The listed protocols sounds good to me. If you want complete list of protocols which runs on each layer then click on the below links for each layer.

Protocols run on Session layer:

http://en.wikipedia.org/wiki/Application_layer

http://en.wikipedia.org/wiki/Session_layer

http://en.wikipedia.org/wiki/Presentation_layer

http://en.wikipedia.org/wiki/Transport_layer

http://en.wikipedia.org/wiki/Network_layer

http://en.wikipedia.org/wiki/Datalink_layer

http://en.wikipedia.org/wiki/Physical_layer

HTH

Regards

Inayath

*Plz rate the usefull posts and close the thread if no further info is needed.

Beginner

OSI and TCP/IP model

That's why i made this table because some of the protocols in wikipedia are misleading like for example the "ethernet" both can be found in physical and data link layer.

Rising star

OSI and TCP/IP model

Hello,

http://www.netsky.org/ipl.jpg

http://www.protocols.com/pbook/tcpip1.htm

Best Regards

Please rate all helpful posts and close solved questions

Best Regards Please rate all helpful posts and close solved questions
Rising star

OSI and TCP/IP model

You can check the following link for more detail about OSI model and protocol stak which works on different layer.


http://en.wikipedia.org/wiki/OSI_model

Beginner

Hi Rivan,

Hi Rivan,

I have this problem too. Some of the protocols in wikipedia are confusion. On the one hand, ARP deals with MAC address, which are part of layer 2. On the other hand, ARP deals with IP address, which are part of layer 3. The TCP/IP layer model offers an answer: layer 2 is a network interface layer between IP and hardware. ARP fits nicely into the definition because it provides the address interface function.

Best Regards,

Shao-Li

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