10-20-2017 11:49 AM - edited 03-08-2019 12:26 PM
Dear All
a question.
According to Wendell Odom-100-105 official cert guilde book.
class A address private IP networks- 10.0.0.0
class B address private IP networks- 172.16.0.0 - 172.31.0.0
class C address private IP networks- 192.168.0.0 - 192.168.255.0
On a respected web page, the values are:
| class A | 10.0.0.0 – 10.255.255.255 | |
| class B | 172.16.0.0 – 172.31.255.255 | |
| class C | 192.168.0.0 – 192.168.255.255 |
which is the correct value, I am asking this, because I am trying to answer below question
I make the answer to be c and d, based on wendell odom's book, can you assist?
many thanks
Arcaneuk10
Solved! Go to Solution.
10-22-2017 05:16 AM - edited 10-22-2017 05:18 AM
Hi
I think it can be interpretated, based on your information the information is not wrong, because he is mentioning just the networks associated to these ranges, for example:
Networks into these ranges are:
Class A 10.0.0.0
Class B 172.16.0.0 to 172.31.0.0
So you will have: 172.16.0.0/16
172.17.0.0/16
172.18.0.0/16
.
.
172.31.0.0/16
Class C 192.168.0.0 to 192.168.255.0
basically the same like Class B
Now the other way to represent that is including all the networks along with the IP addresses into these ranges
Class A 10.0.0.0 to 10.255.255.255
Class B 172.16.0.0 to 172.31.255.255
Class C 192.168.0.0 to 192.168.255.255
Basically
In Class A you can modify the Octet 2,3 and 4 but not the octet 1
in Class B you can modify the Octet 2,3,4 but not the octet 1 and you have restrictions with the octet 2 where you can modify them with values from 16 to 31, now 32 will not be part of this range.
in Class C you can modify the Octet 3 and 4.
Hope it is useful
:-)
10-23-2017 05:14 AM
Hi
It was a pleasure my friend, have a great day.
:-)
10-23-2017 09:53 AM
Hi Joseph
Many thanks, I do get it now, very grateful for the info, thank you.
Regards
Arcaneuk10
10-20-2017 12:12 PM - edited 10-20-2017 01:08 PM
Hi
The 172.33.1.254 is a public IP address.
As you know the ranges are:
10.0.0.0 to 10.255.255.255
172.16.0.0 to 172.31.255.255
192.168.0.0 to 192.168.255.255
So 172.33.1.254 is not part of none network above. It can considered as a Public IP address.
And the second is D, because 192.186.2.0 is not a private IP by the second octet. That is a visual trick (a private IP is 192.168 no 192.186)
So the answers should be B and D
Hope it is useful
:-)
10-22-2017 01:56 AM
Hi Julio
Thanks for the reply, I get that now, it makes sense to me if I follow the web page with the following:
10.0.0.0 to 10.255.255.255
172.16.0.0 to 172.31.255.255
192.168.0.0 to 192.168.255.255
I did not understand it based on wendell odom's page, should I follow what the above ranges are, and not the wendell odom page on private lan ranges, because as you can see they are both different, I hope I am making sense here.
Regards
Arcaneuk10
10-22-2017 05:16 AM - edited 10-22-2017 05:18 AM
Hi
I think it can be interpretated, based on your information the information is not wrong, because he is mentioning just the networks associated to these ranges, for example:
Networks into these ranges are:
Class A 10.0.0.0
Class B 172.16.0.0 to 172.31.0.0
So you will have: 172.16.0.0/16
172.17.0.0/16
172.18.0.0/16
.
.
172.31.0.0/16
Class C 192.168.0.0 to 192.168.255.0
basically the same like Class B
Now the other way to represent that is including all the networks along with the IP addresses into these ranges
Class A 10.0.0.0 to 10.255.255.255
Class B 172.16.0.0 to 172.31.255.255
Class C 192.168.0.0 to 192.168.255.255
Basically
In Class A you can modify the Octet 2,3 and 4 but not the octet 1
in Class B you can modify the Octet 2,3,4 but not the octet 1 and you have restrictions with the octet 2 where you can modify them with values from 16 to 31, now 32 will not be part of this range.
in Class C you can modify the Octet 3 and 4.
Hope it is useful
:-)
10-23-2017 04:11 AM
Hi Julio
Thank you, that makes sense to me now.
very grateul for your help.
Regards
Arcaneuk10
10-23-2017 05:14 AM
Hi
It was a pleasure my friend, have a great day.
:-)
10-23-2017 09:53 AM
Hi Joseph
Many thanks, I do get it now, very grateful for the info, thank you.
Regards
Arcaneuk10
10-23-2017 08:22 AM
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