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Question on Lesson 10.7 activity

Centripucoloso
Level 1
Level 1

‎07-24-2012 07:37 PM - edited ‎03-07-2019 07:57 AM

On this problem I have subnet the given ip, connect router 1 and 2 but 2 and 3 seems to be difficult to be connect because I get confused on the subneting. I have 60 percent of this problem but I won't pass that percent. I am stuck anybody can give me a hand.

THE PROBLEM...

10.7.1: Skills Integration Challenge-Network Planning and Interface Configuration

DeviceInterfaceIP AddressSubnet MaskDefault Gateway
R1Fa0/0

N/A
S0/0/0

S0/0/1

R2Fa0/0

N/A
Fa0/1

S0/0/0

S0/0/1

R3Fa0/0

N/A
S0/0/0

S0/0/1

PC-1ANIC


PC-1BNIC


PC-1CNIC


Eagle_ServerNIC


Learning Objectives:

  • Build the network topology
  • Plan the IP addresses
  • Configure router and PC interfaces
  • Test the network

Background:

Practice your network building, planning, and configuration skills. Device names and routing have already been configured.

Task 1: Build the network topology

Use the following chart, and the devices in the Device Pool, to create the topology.Routers:

HostnameInterfaceConnects ToInterface
R1Fa0/0SW-1Fa0/1
R1S0/0/0 (DCE)R2S0/0/0
R1S0/0/1 (DCE)R3S0/0/1
R2Fa0/0SW-2AFa0/1
R2S0/0/1 (DCE)R3S0/0/0
R2Fa0/1SW-2BFa0/1
R3Fa0/0SW-3Fa0/1

Switches:

HostnameInterfaceConnects ToInterface
SW-1Fa0/2PC-1AFastEthernet
SW-2AFa0/2PC-1BFastEthernet
SW-2BFa0/2Eagle_ServerFastEthernet
SW-3Fa0/2PC-1CFastEthernet

Task 2: Create and assign an addressing scheme

You are asked to use the 192.168.1.0 /24 address space. Seven total networks are required; assign the networks in decreasing order of number of hosts required for efficient use of address space. Use the following charts to create an effective addressing scheme:LAN:

HostnameInterfaceNumber of Hosts
R1Fa0/060
R2Fa0/010
Fa0/125
R3Fa0/07

WAN:

WAN LinksAddress to be AssignedNumber of Hosts
R1-R2R1-First host address2
R1-R3R1-First host address2
R2-R3R2-First host address2

Use the following rules to assign the IP addresses.

  • PC's will use the first host address in the subnet.
  • The server will use the second to last host address in its subnet.
  • All FastEthernet ports on a router will use the last host address of the assigned subnet.
  • The R1-R2 link will use the first WAN subnet, with R1 using the first usable address and R2 using the last usable address.
  • The R1-R3 link will use the second WAN subnet, with R1 using the first usable address and R3 using the last usable address.
  • The R2-R3 link will use the third WAN subnet, with R2 using the first usable address and R3 using the last usable address.
  • DCE interfaces should have clock rates of 56000.

Task 3: Interface Configuration

Perform interface configuration of the R1, R2, and R3 routers, the PCs, and the server according to the addressing scheme above.

Task 4: Testing Connectivity

Make sure all PCs can ping their gateways, other PCs, and the server.

All contents are Copyright © 2007–2009 Cisco Systems, Inc. All rights reserved. This document is Cisco Public Information.

Labels:
0 Helpful
12 Replies 12

jimmysands73_2
Level 5
Level 5

‎07-24-2012 09:24 PM

I would recommend Cisco Learning Network for this type of question.....its more of student forum.  But since your here!,

what part are you getting stuck with?  Just th concept in general?

To get subnetting you really have to do question after question after example after example after question after example after question after question after example after example after question after example...you get the point.

Here is a site I used alot:

http://www.subnettingquestions.com/

It sounds to me as if you might be confused with the concept of subnetting in general....does the concept confuse you or the math?

0 Helpful

Centripucoloso
Level 1
Level 1
In response to jimmysands73_2

‎07-26-2012 07:09 AM

What confused me was the math, the sequence of events. I tend to confuse the assigning the first usable host, with the network part and the broadcast address.. therefore the math tend to get confuse in between subnets.

0 Helpful

cadet alain
VIP Alumni
VIP Alumni

‎07-24-2012 11:23 PM

Hi,

192.168.1.0/24

1st subnet: 60 hosts

==>6 host bits ==> 32-6=26 ==> /26 ==> 255.255.255.192

so the available subnets are:

192.168.1.0/26

192.168.1.64/26

192.168.1.128/26

192.168.1.192/26

we take the first one for R1 f0/0: 192.168.1.0/26

All FastEthernet ports on a router will use the last host address of the assigned subnet.

==>the available adresses are 192.168.1.1- 192.168.1.62 ==> f0/0 R1 is 192.168.1.62/26

2nd subnet: 25 hosts

==> 5 host bits ==> 32-5=27 ==> /27 ==> 255.255.255.224

so the available subnets are:

192.168.1.64/27

192.168.1.96/27

192.168.1.128/27  and so on

==> we take the first one:192.168.1.64/27 : 192.168.1.65-192.168.1.94

==> R2 f0/1 is 192.168.1.94/27

3rd subnet: 10 hosts

==> 4 host bits ==> 32-4=28 ==> /28 ==> 255.255.255.240

so the available subnets are:

192.168.1.96/28

192.168.1.112/28

192.168.1.128/28

192.168.1.144/28

and so on

==> R2 f0/0 is 192.168.1.110/28

4th subnet: 7 hosts

==> 4 host bits => /28 ==>255.255.255.240

available subnet is 192.168.1.112/28 ==> R3 f0/0 is 192.168.1.126/28

Now for the serial links we need /30 subnets

for that we subnet 192.168.1.128/28 which gives us:

192.168.1.128/30: 192.168.1.129-192.168.1.130

192.168.1.132/30: 192.168.1.133-192.168.1.134

192.168.1.136/30: 192.168.1.137-192.168.1.138

==>R1-R2  R1 is 192.168.1.129/30 and R2 is 192.168.1.130/30

   R1-R3: R1 is 192.168.1.133/30 and R3 is 192.168.1.134/30

   R2-R3: R2 is 192.168.1.137/30 and R3 is 192.168.1.138/30

Regards.

Alain

Don't forget to rate helpful posts.

Don't forget to rate helpful posts.

Centripucoloso
Level 1
Level 1
In response to cadet alain

‎07-26-2012 07:11 AM

Thank you for your great explanantion though I didn't understand this

2nd subnet: 25 hosts


==> 5 host bits ==> 32-5=27 ==> /27 ==> 255.255.255.224

Why you substract -5 from 32?

0 Helpful

cadet alain
VIP Alumni
VIP Alumni
In response to Centripucoloso

‎07-26-2012 07:41 AM

Hi,

because an IPv4  address is 32 bits long and I need to leave 5 bits for the hosts to have enough usable addresses

and so the rest are network + subnetwork bits which gives me the prefix-length that I can then equate to subnet mask.

Regards.

Alain.

Don't forget to rate helpful posts.

Don't forget to rate helpful posts.

Centripucoloso
Level 1
Level 1
In response to cadet alain

‎07-26-2012 07:32 PM

Are the links connected through the S/0/0?

0 Helpful

cadet alain
VIP Alumni
VIP Alumni
In response to Centripucoloso

‎07-26-2012 10:50 PM

which links are you talking about ?

Regards.

Alain

Don't forget to rate helpful posts.

Don't forget to rate helpful posts.
0 Helpful

Centripucoloso
Level 1
Level 1
In response to cadet alain

‎07-27-2012 05:43 AM

i am talking about the serials links i don't understand why the program tracer is saying that the ip are overlapping, specially the links ones after the sunbnet .129

0 Helpful

burleyman
Level 8
Level 8
In response to Centripucoloso

‎07-27-2012 06:24 AM

Hope this clears it up....I will leave the rest to you.

Mike

Requirements in Decending orderSubnet with a mask ofNetwork Address                 (Not a usable IP Address)Broadcast Address                 (Not a usable IP Address)Total number of IP addressesUsable IP addresses
60 host subnet192.168.1.0255.255.255.192192.168.1.0192.168.1.636462
25 host subnet192.168.1.64255.255.255.224192.168.1.64192.168.1.953230
10 host subnet192.168.1.96255.255.255.240192.168.1.96192.168.1.1111614
7 host subnet192.168.1.112255.255.255.240192.168.1.112192.168.1.1271614
2 host network Serial connection from R1 to R2192.168.1.128255.255.255.252192.168.1.128192.168.1.13142
2 host network Serial connection from R1 to R3192.168.1.132255.255.255.252192.168.1.132192.168.1.13542
2 host network Serial connection from R2 to R3192.168.1.136255.255.255.252192.168.1.136192.168.1.13942
0 Helpful

Centripucoloso
Level 1
Level 1
In response to burleyman

‎07-27-2012 06:35 AM

i will get on it right now thanks for the push and homework left.

0 Helpful

burleyman
Level 8
Level 8
In response to Centripucoloso

‎07-27-2012 06:39 AM

Just make sure you understand what I did for future.

Remember to rate helpful posts... 

Mike

Centripucoloso
Level 1
Level 1
In response to burleyman

‎07-27-2012 07:55 AM

i am 97% percent now. i did understood the sequence of event which is in

LAN:

HostnameInterfaceNumber of Hosts
R1Fa0/060
R2Fa0/010
Fa0/125
R3Fa0/07

WAN:

WAN LinksAddress to be AssignedNumber of Hosts
R1-R2R1-First host address2
R1-R3R1-First host address2
R2-R3R2-First host address2

i was getting the subnetting all mixed up and didn't know which one to subenet first. your and cadet where extremenly helpful and now i  know that for the future i will have to follow that sequence.

The only thing that appear to be missing is the type for the switches

When i click on check results there is a tab called type which has an red X indicating that i have to configure that part i don't know what to put. i don;t know if they mean DNS and Http server settings.

Never mind.........

the type refered to the cable. i was connecting the switch with the server with a cross over cable and it needed a straight through cable...

0 Helpful
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