06-02-2008 05:28 PM - edited 03-05-2019 11:22 PM
I dont have a lab right now to lab it up, so I need some expertise...
with the statement
ip nat inside source static network 10.0.0.0 3.0.0.0/24
any address on the 10.0.0.0 network will get NATed to an address on the 3.0.0.0 network, correct?
But how are the 3.0.0.0 address allocated? In numerical order?
Thanks
Victor
Solved! Go to Solution.
06-02-2008 05:42 PM
Victor
In NAT using the static and network combination the host bits of the source address are mapped directly to the bits of the translated address. So if you had address 10.22.33.44 it would be translated into 3.22.33.44.
HTH
Rick
06-02-2008 05:42 PM
Victor
In NAT using the static and network combination the host bits of the source address are mapped directly to the bits of the translated address. So if you had address 10.22.33.44 it would be translated into 3.22.33.44.
HTH
Rick
06-02-2008 06:01 PM
O, OK..
So, its just a one for one then...
So, you would really use this when you want to make a sweeping NAT of an entire network, right?
VL
06-02-2008 06:07 PM
Victor
right
HTH
Rick
06-02-2008 06:23 PM
OK, thanks, Rick. Appreciate the sanity check.
Have a great night.
Victor
Discover and save your favorite ideas. Come back to expert answers, step-by-step guides, recent topics, and more.
New here? Get started with these tips. How to use Community New member guide