What Deepak shows is fine, but I just wanted to add there's more combinations.
For example, since a /25 will consume half of your /24, you have a choice of whether to use the top/1st half (as Deepak did) or the bottom/2nd half (which would be 172.16.1.128/25).
Depending on which half of the /24 you use, your remaining free /25 provides a top/1st and a bottom/2nd /25. Again, you can use either, and also again Deepak chose to use the remaining top/1st /25.
Lastly you have the /28 to allocate. After you've allocated your /25 and /26, you have a /26 of free space within your original /24 block, which supports four /28s. You could use any of those four.
However it can get "tricky", not technically, but regarding planning space allocation. Let's say you need to allocate two /28s out of your remaining /26. If you chose the the first and last available /28, although you would have a /27's worth of continuous IP space, you could not allocated it as a /27. To preserve the option to allocate it as a /27, your two /28s should be allocated as the first two or last two blocks of the /26.
