06-08-2005 07:03 AM - edited 03-03-2019 09:46 AM
I have here a cbwfq config on a 384kbps pvc. I don't understand why the router says there is 96kbps bandwidth available. Could someone explain?
router#sh queueing int atm1/0.14 vc 0/113
Interface ATM1/0.14 VC 0/113
Queueing strategy: weighted fair
Output queue: 0/96/64/2497 (size/max total/threshold/drops)
Conversations 0/19/32 (active/max active/max total)
Reserved Conversations 1/1 (allocated/max allocated)
Available Bandwidth 96 kilobits/sec <-------------------------- why only 96kbps?
This is the config:
!
ip access-list extended ospf
permit ospf any any
!
class-map match-all ospf
match access-group name ospf
!96*
!
policy-map wfq
class ospf
bandwidth percent 50
class class-default
fair-queue
random-detect
!
interface ATM1/0.14 point-to-point
bandwidth 384
ip address x.x.x.x 255.255.255.252
ip mtu 1500
no ip mroute-cache
pvc 0/113
vc-hold-queue 96
protocol ip y.y.y.y broadcast
vbr-nrt 482 384
encapsulation aal5snap
service-policy output wfq
!
end
06-08-2005 09:59 AM
Hi, try a 'show policy-map interface atm1/0.14 point to point'. You may see closer to the allocated bandwidth you are looking for.
06-09-2005 05:28 AM
The available bandwidth is really nothing but a math formula that the router uses. For a normal interface it takes whatever you have under the bandwidth statement and then automatically takes 25% off (for admin overhead and routing protocols) of it to give you the available bandwidth. If you have any QoS setup it will subtract that too. It is morless a call admission control thing.
06-09-2005 11:12 AM
So, it is the bandwidth I have _left_ rather than available in total. Is that correct? Would that bandwidth be assigned to the default class in this case? Assuming congestion conditions, ofcourse.
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