VLAN 60: 10.20.213.64/28 excluded address : 10.20.213.65 - .69
VLAN 80: 10.20.210.0/23 excluded address : 10.20.210.1 - .15
VLAN 60 (HOST PC) : 10.20.213.66
VLAN 80 (HOST PC) : 10.20.210.2
Backbone network LAN C : 10.20.208.0/23
For static :
i am supposed to map the assigned private address of VM2 to 10.20.208.50
Configure the NAT inside network on G0/0 on R2
Configure the NAT outside network on interface G0/1 on R2
This is my command:
en
config t
ip nat inside source static 10.20.213.66 10.20.208.50
end
config t
int g0/0
ip nat inside
int g0/1
ip nat outside
end
For Dynamic :
i am supposed to create standard acl 2 to allow ip address of pc 2 to do NAT translation.
Create a a public pool of ip address from <lan c network address> .80 to .90
Name it as Earpool and map acl 2 to it for NAT translation
Configure NAT inside network on the appropriate sub-interface on g0/0 on R2
Configure NAT outside network on interface g0/1 on R2
This is my command : en
config t
access-list 2 permit 10.20.213.64 0.0.0.15
ip nat pool Earpool 10.20.208.80 10.20.208.90 netmask 255.255.254.0
ip nat inside source list 2 pool Earpool
int g0/0.50
ip nat inside
int g0/0.60
ip nat inside
int g0/1
ip nat outside
end
What i am supposed to achieve FOR STATIC is : A host in public (VLAN 80) is able to access the web server VM2 using public static ip 10.20.208.50
What i am supposed to achieve FOR DYNAMIC is : Open a browser in PC2, enter pc 1 or vm1 ip address in the URL.
FYI: My pc is in DHCP so the ip address is 10.20.213.70
My vm2 is in static so the ip address is 10.20.213.66
Please advice if my command is wrong OR my settings is wrong.
