Hello,
this exercise is an subnetting example. You must divide your range 192.168.0.0/27 (32 addresses) in
two subnets to support 10 hosts (subnet 16 addresses) and 5 hosts (subnet 8 address):
3-1. 192.168.0.0/28. Last address is broadcast 192.168.0.15 so the last usable address for hosts is 192.168.0.14.
3-2. 192.168.0.16/29. Last address is broadcast 192.168.0.23 so the last usable address for hosts is 192.168.0.22.
3-3 For Fa0/0 the first host ip address is 192.168.0.1 and for Fa0/1 is 192.168.0.17.
Notice that we have use the first /28 subnet because if you use the 192.168.0.16/28 a overlapping problem
exist (with subnet /30 Serial0/1/0 in Ranter-BR1-1).
Regards