09-28-2013 07:27 AM - edited 03-07-2019 03:43 PM
Hi All,
Just a quick one, I am little bit confused with the following subnetting question.
192.168.8.33/23
Need to calculate the following:
No of Hosts:
No of subnets:
Network ID:
Subnet mask:
Actually they asked me in an interview.
Any help will be much appreciated.
Thanks.
Sent from Cisco Technical Support iPhone App
09-28-2013 12:11 PM
Hi,
Number of hosts: 32-23=9 so 2exp9-2=510
Number of subnets= 2 class C subnets which are 192,168,8,0 and 192,168,9,0
Network id= 192.168.8.0
subnet mask= 255.255.254.0
Regards
Alain
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09-28-2013 12:38 PM
Hi,
I did not get how did u calculate the two subnets.
Could you please explain that,
Would be much helpful.
Many thanks.
Sent from Cisco Technical Support iPhone App
09-28-2013 12:50 PM
Hi
This is a supernet as the prefix length is less than the class so it represents the 2 class C networks because 24 minus 23 is 1 so 2 exp1 is 2
Regards
Alain
Don't forget to rate helpful posts.
09-28-2013 12:57 PM
Hi,
Thank you ever so much for the info.
How would we know that the two networks would be ?
192.168.8.0
192.168.8.0
Many thanks.
Sent from Cisco Technical Support iPhone App
09-28-2013 02:05 PM
Sorry I mean
192.168.8.0 and 192.168.9.0
Sent from Cisco Technical Support iPhone App
09-30-2013 01:09 AM
Hi,
As of my knowledge. Two networks are deteremined like this way.
As 1 bit is used for supernetting. 2 power 1 = 2. So we have two subnets consisting of 510 hosts.
Subnets range:
192.168.0.0 - 192.168.1.255
192.168.2.0- 192.168.3.255
192.168.4.0 - 192.168.5.255
192.168.6.0 - 192.168.7.255
192.168.8.0 - 192.168.9.255
192.168.10.0 - 192.168.11.255....
Since this 192.168.8.33/23 is the given address it falls in the range : 192.168.8.0 - 192.168.9.255..
Hope my explanation is fine.
Please rate.
Regards,
Chandu
10-04-2013 01:01 PM
hi,
a brief answer for your question as a below:
No of Hosts: 510
No of subnets: 1
Network ID: 192.168.8.0
Subnet mask: 255.255.254.0
HostMin: 192.168.8.1
HostMax: 192.168.9.254
regards,
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