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Helpful
3
Replies

E1 INTER-BRANCH CONNECTION(OUTGOING)

isaaco001
Level 3
Level 3

Dear Community,

I have been able to connect two branches using dial-peers:

branch 1 to branch 2 

dial-peer voice 4 voip
destination-pattern 3..
session protocol sipv2
session target ipv4:192.168.16.240
dtmf-relay rtp-nte
codec g711ulaw
no vad

branch 2 to branch 1

dial-peer voice 4 voip
destination-pattern 1..
session protocol sipv2
session target ipv4:192.168.33.248
dtmf-relay rtp-nte
codec g711ulaw
no vad

branch 1 has the following E1 dial-peer

dial-peer voice 7 pots

corlist outgoing outgoing-call

translation-profile outgoing cucmepstn

destination-pattern 2T

port 0/1/0:15

incoming calls from PSTN to branch 2 through E1 is working,how can i make outgoing calls to PSTN work through E1 from branch 2?

Thank you all!

1 Accepted Solution

Accepted Solutions

Suresh Hudda
VIP Alumni
VIP Alumni

Create another voip dial peer in branch 2 and set destination pattern 9.t (e.g. 9 access code) and point it to branch 1, the branch 1 create pots dial peer and set destination pattern 9.T and point to e1 pri.

Suresh

View solution in original post

3 Replies 3

Suresh Hudda
VIP Alumni
VIP Alumni

Create another voip dial peer in branch 2 and set destination pattern 9.t (e.g. 9 access code) and point it to branch 1, the branch 1 create pots dial peer and set destination pattern 9.T and point to e1 pri.

Suresh

Hi,once again you are right indeed.

Hi,

How can i redirect a call from one busy dial-peer to another dial-peer with a different destination-pattern but free channels in CME.In the example below dial-peer 1 is an E1 with more channels but has higher call rates(expensive),however i want dial-peer 2 to be used first(cheaper call charges) and if busy because of just that one port the call should go to dial-peer 1 automatically.How can this be done in CME.

dial peer 1

dial-peer voice 5 pots
destination-pattern 907[0-2,9].......
translation-profile outgoing cucmepstn

port 0/1/0:15

dial-peer 2

dial-peer vioce 6 pots

destination-pattern 907[3,5].......

por 0/1/0

Thank you.