05-04-2005 10:56 PM - edited 03-03-2019 09:29 AM
Hi,I haven't a good way to generate default route in my eigrp environment. who can tell me?Thanks a lot
Sincerely
05-04-2005 11:36 PM
Hi,
default route's are not part of any dynamic routing protocol i.e EIGRP, OSPF etc..but is a static route that is configured like this
ip route 0.0.0.0 0.0.0.0 "ip address of internet gateway"
so for instance
ip route 0.0.0.0 0.0.0.0 192.168.1.1
05-05-2005 07:03 AM
Try something like this:
access-list standard eigrpdefualt
permit 0.0.0.0
deny any
Then use a distribute list out to your neighbors who you want to get a default route.
05-05-2005 07:34 AM
dont access lists deny all that is not permitted ? so "deny any" is not needed
and forgive me if i am wrong but is that not just going to distribute out the access-list to all routers in the EIGRP AS and ultimating just allow packets out, not direct packets with an unknown destination to a specified gateway?
Nathan
05-05-2005 07:53 AM
Yes the deny any is implicit, but I like to use it. That basically comes down to preference.
The defualt route I am referring to is usually used in a hub and spoke environment where the spokes do not need the entire routing table, and can save resources be just getting a external eigrp default route sent to them.
This is what will show up in the routing table for the spoke router:
D*EX 0.0.0.0/0 [170/2179072].........
05-05-2005 08:08 AM
Ok, I see where your going with this. your on about stub sites that only have one exit out and are not meshed in any way
05-05-2005 11:11 AM
You can also generate a default summary to the neighbors that you want to see a default route by adding the following statement to the interfaces where the neighbors are located:
ip summary-address eigrp x 0.0.0.0 0.0.0.0
Just replace the "x" with your eigrp process number.
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