- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
01-20-2013 07:20 PM - edited 03-04-2019 06:46 PM
Hi,
In connection to my last post, I somehow read about the discontiguous network. When I saw the network I made, I think it is a discontiguous network. I thought RIP won't work but I can ping each others host.
Here is my network configured by RIP.
Can someone enlighten me about discontiguous network? And in my case why did RIP is still sending/receiving route updates?
Thanks.
Solved! Go to Solution.
- Labels:
-
Other Routing
Accepted Solutions
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
01-20-2013 09:40 PM
Hi,
If you are running RIPv1:
1. In your network regardless of auto-summary option both routers will advertise 192.168.16.0/192.168.8.0 with /24 mask as it is class C network. Because RIPv1 do not advertise with prefixes.
2. There could be a problem if on both sides e.g. subnets 192.168.8.0/25 and 192.168.8.128/25. When router receives update it check whether it has an interface on this subnet. If it has already then it ignores the update. Because these subnets advertised with /24 mask.
RIPv2:
1. version 2, advertise subnets with prefixes. If an update did cross major network boundary with auto-summary option it will summarize subnets. If did not then regardless of auto summary it won't summarize.
Hope it will help.
Best regards,
Abzal
Abzal
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
01-20-2013 10:05 PM
Hi,
In connection to my last post, I somehow read about the discontiguous network. When I saw the network I made, I think it is a discontiguous network. I thought RIP won't work but I can ping each others host.
Just to make everything clear, yes, the network you have made is indeed a discontiguous network.
But as Abzal have said, it WILL work in any case (RIPv1,RIPv2) because 192.168.x.x are class C networks and as a class C networks - they are expected to have mask of /24.
Best regards,
Jan
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
01-20-2013 11:04 PM
Yes, it's correct.
Imagine you have a subnet 10.1.1.0/24 on 10.0.0.2 router.
With RIPv2 there shouldn't be a problem. Because it would arvertise this subnet with a prefix (/24). And 10.0.0.1 router would add it to RIB(routing table).
But with RIPv1 it wouldn't see this subnet because second router would advertise subnet without a prefix, just 10.0.0.0/8. So router would not accept it and to RIB as it has already subnet on interface.
Hope it will help.
Best regards,
Abzal
Abzal
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
01-20-2013 09:40 PM
Hi,
If you are running RIPv1:
1. In your network regardless of auto-summary option both routers will advertise 192.168.16.0/192.168.8.0 with /24 mask as it is class C network. Because RIPv1 do not advertise with prefixes.
2. There could be a problem if on both sides e.g. subnets 192.168.8.0/25 and 192.168.8.128/25. When router receives update it check whether it has an interface on this subnet. If it has already then it ignores the update. Because these subnets advertised with /24 mask.
RIPv2:
1. version 2, advertise subnets with prefixes. If an update did cross major network boundary with auto-summary option it will summarize subnets. If did not then regardless of auto summary it won't summarize.
Hope it will help.
Best regards,
Abzal
Abzal
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
01-20-2013 10:05 PM
Hi,
In connection to my last post, I somehow read about the discontiguous network. When I saw the network I made, I think it is a discontiguous network. I thought RIP won't work but I can ping each others host.
Just to make everything clear, yes, the network you have made is indeed a discontiguous network.
But as Abzal have said, it WILL work in any case (RIPv1,RIPv2) because 192.168.x.x are class C networks and as a class C networks - they are expected to have mask of /24.
Best regards,
Jan
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
01-20-2013 10:27 PM
Thank You!
I understand that RIP will summarize the network to /24 because it is a class c address, I was more concerned in the 10.0.0.0 network and then I realized it will not affect both 192.168.8.0 and 192.168.16.0 network right? Since it is only like a bridge on both network (not a bridge device function). Am i correct?
Thanks.
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
01-20-2013 11:04 PM
Yes, it's correct.
Imagine you have a subnet 10.1.1.0/24 on 10.0.0.2 router.
With RIPv2 there shouldn't be a problem. Because it would arvertise this subnet with a prefix (/24). And 10.0.0.1 router would add it to RIB(routing table).
But with RIPv1 it wouldn't see this subnet because second router would advertise subnet without a prefix, just 10.0.0.0/8. So router would not accept it and to RIB as it has already subnet on interface.
Hope it will help.
Best regards,
Abzal
Abzal
